Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If 4x + 5y = 14 and x - 5y = 16 then the value of x and y are

A) 10 and -6/5 B) 6 and 2
C) 10 and 6/5 D) 6 and -2
 
Answer & Explanation Answer: D) 6 and -2

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Q:

If x - 2y = 2 and 3x + y = 20, then the value of (x,y) is

A) (6, 2) B) (4, 1)
C) (3, 2) D) (5, 5)
 
Answer & Explanation Answer: A) (6, 2)

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Q:

Simplify (b2x 3a2z4 ) × (b2x 4a4z3 )/(a3b2z4 )

A) b2x7a3z3 B) b3x7a3 z3
C) b2x5a3 z3 D) b2x7a3z2
 
Answer & Explanation Answer: A) b2x7a3z3

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Q:

The average revenues of 13 consecutive years of a company is Rs 70 lakhs. If the average of first 7 years is Rs 65 lakhs and that of last 7 years is Rs 77 lakhs, find the revenue for the 7th year.

A) Rs 86 lakhs B) Rs 84 lakhs
C) Rs 82 lakhs D) Rs 80 lakhs
 
Answer & Explanation Answer: B) Rs 84 lakhs

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Q:

If  2x+14x = 1, then the value of  x2+164x2 is

A) 0 B) 1
C) 1/4 D) 2
 
Answer & Explanation Answer: A) 0

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Q:

9997 x 10003 = ?

A) 9999991 B) 99999911
C) 99999991 D) 9999911
 
Answer & Explanation Answer: C) 99999991

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Q:

If 7 + 3x ≥ 5 ­- x/2 and 2x + 3 ≤ 5 -­ 2x; then x can take which of the following values?

A) 0 B) 1
C) 2 D) -1
 
Answer & Explanation Answer: A) 0

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Q:

If (x ­- 2) (x -­ p) = x2 - ax + 6, then the value of (a -­ p) is

A) 0 B) 1
C) 2 D) 3
 
Answer & Explanation Answer: C) 2

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