Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If y = 13 + 23 + 33 + 43 + 53 + 63 then find the value of y - 1.

 

A) 429 B) 439
C) 440 D) 441
 
Answer & Explanation Answer: C) 440

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Q:

If x2 + kx + k = 0 has repeated roots, then the value of k will satisfy :

 

 

A) k<0 or k>4 B) k=4 only
C) 0<k<4 D) k=4 or k=0
 
Answer & Explanation Answer: D) k=4 or k=0

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Q:

If y - 1y  = 4, then find the value of y3 - 1y3.

 

A) 64 B) 76
C) 88 D) 90
 
Answer & Explanation Answer: B) 76

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Q:

Calculate the value of x if 1 - x289 = 1517

 

A) 64 B) 44
C) 36 D) 54
 
Answer & Explanation Answer: A) 64

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Q:

The two equations x - 4y = 0 and 4x + 3y = 19 have a solution (a, b). Find the value of aba + 4b.

 

A) 1/4 B) 1/2
C) 1 D) 23
 
Answer & Explanation Answer: B) 1/2

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Q:

Use continuity to evaluate the limit.

limx128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx128+x8+x = 8+128+12= 1.

 

 

 

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Q:

Which of the following statement(s) is/are TRUE?

 

I. 225 + 441256 > 2.5II. 289 + 529169 > 3

 

A) Only I   B) Only II  
C) Neither I nor II D) Both I and II
 
Answer & Explanation Answer: B) Only II  

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Q:

What is the simplified value of 

117-16-116-15+115-14-114-13+113-12 ?

A) 4 – 2√3 B) √17 – 3√2
C) √17 + √12 D) 4 + 2√3
 
Answer & Explanation Answer: C) √17 + √12

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