Ratios and Proportions Questions

FACTS  AND  FORMULAE  FOR  RATIO  AND  PROPORTION  QUESTIONS

 

 

1. RATIO: The ratio of two quantities a and b in the same units, is the fraction a/b and we write it as a:b.

In the ratio a:b, we call a as the first term or antecedent and b, the second term or consequent.

Ex. The ratio 5: 9 represents 5/9 with antecedent = 5, consequent = 9.

Rule: The multiplication or division of each term of a ratio by the same non-zero number does not affect the ratio. Ex. 4: 5 = 8: 10 = 12: 15 etc. Also, 4: 6 = 2: 3.

 

2. PROPORTION : The equality of two ratios is called proportion

If a: b = c: d, we write, a: b :: c : d and we say that a, b, c, d are in proportion . Here a and d are called extremes, while b and c are called mean terms.

Product of means = Product of extremes.

Thus, a: b :: c : d <=> (b x c) = (a x d).

 

 3(i) Fourth Proportional : If a : b = c: d, then d is called the fourth proportional to a, b, c.

     (ii) Third Proportional : If a: b = b: c, then c is called the third proportional to a and b.

     (iii) Mean Proportional : Mean proportional between a and b is ab

 

 4. (i) COMPARISON OF RATIOS : We say that (a: b) > (c: d)  (a/b)>(c /d).

     (ii) COMPOUNDED RATIO : The compounded ratio of the ratios (a: b), (c: d), (e : f)  is    (ace: bdf)

 

5. (i) Duplicate ratio of (a : b) is a2:b2.

    (ii) Sub-duplicate ratio of (a : b) is (√a : √b).

    (iii)Triplicate ratio of (a : b) is a3:b3.

    (iv) Sub-triplicate ratio of (a : b) is a13: b13.

    (V) If ab=cd, thena+ba-b=c+dc-d (Componendo and dividendo)

 

 6. VARIATION:

(i) We say that x is directly proportional to y, if x = ky for some constant k and we write, xy

(ii) We say that x is inversely proportional to y, if xy = k for some constant k and we write, x1y

Q:

If a=2b/3, b=2c/3, and c=2d/3, then find the ratio of b and d:

 

A) 8/9 B) 4/9
C) 4/3 D) 5/27
 
Answer & Explanation Answer: B) 4/9

Explanation:
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3 10940
Q:

Choose the CORRECT option about the two tangents drawn to the circle from the external point?

(1) The tangents subtend equal angles at the centre of the circle.

(2) The tangents drawn from the external point to a circle are equal in length.

(3) The tangents are equally inclined to the segment which joins the centre to that point.

A) 1 and 2 only B) 2 and 3 only
C) 1, 2 and 3 D) 1 and 3 only
 
Answer & Explanation Answer: C) 1, 2 and 3

Explanation:
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0 10619
Q:

16 : 56 :: 32 : ?

A) 196 B) 148
C) 132 D) 112
 
Answer & Explanation Answer: D) 112

Explanation:

16 : 56 :: 32 : ?

Let the required number be 'n'

The given numbers follow a logic that,

16/56 = 2/7

=> 32/n = 2/7

=> 32 x 7/2 = n

=> n = 112.

 

Hence, 16 : 56 :: 32 : 112.

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44 10379
Q:

If k : l = 4 : 3 and l : m = 5 : 3, then find k : l : m ?

A) 18 : 24 : 11 B) 9 : 15 : 1
C) 20 : 15 : 9 D) 21 : 7 : 3
 
Answer & Explanation Answer: C) 20 : 15 : 9

Explanation:

Given k : l = 4 : 3
l : m = 5 : 3

Then k : l : m = 20 : 15 : 9

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12 10309
Q:

If y/(x - z) = (y + x)/z = x/y then find z : y : x ?

A) 1:2:3 B) 3:2:4
C) 4:3:2 D) 2:3:4
 
Answer & Explanation Answer: B) 3:2:4

Explanation:

Given, y/(x - z) = (y + x)/z = x/y
yz = xy + x2 - yz - xz ....(1)
Also xy = yx-z x2 -xz = y2 ....(2)
Using (1) and (2), we get yz = xy - yz + y2
2yz = xy + y2
2z = x + y
Only option (B) satisfies the equation.

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18 9818
Q:

Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided?

A) 7:1 B) 13:5
C) 15:7 D) 2:7
 
Answer & Explanation Answer: A) 7:1

Explanation:

Maneela lent Rs. 8000 in two parts,

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24 9663
Q:

80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 

A) 120 lit B) 140 lit
C) 110 lit D) 150 lit
 
Answer & Explanation Answer: D) 150 lit

Explanation:

To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.

=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres

However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.

i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.

Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

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13 9642
Q:

If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ?

A) 5 B) 4
C) 20 D) 28
 
Answer & Explanation Answer: C) 20

Explanation:

Given (2a + 3b)/(5a - 3b) = 23/5
=> 10a + 15b = 115a - 69b
=> 105a = 84b => 5a = 4b
a/b = 4/5 => a=4 & b=5
=> bxa = 5x4 = 20.

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