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 Problems on Trains Questions

Popular Latest Rated Important Formulae

FACTS  AND  FORMULAE  FOR  PROBLEMS  ON  TRAINS

 

 

1. a km/hr = [a x (5/18)] m/s.

 

2. a m/s = [a x (18/5)] km/hr.

 

3. Time taken by a train of length l metres to pass a pole or a standing man or a signal post is equal to the time taken by the train to cover l metres.

 

4. Time taken by a train of length 1 metres to pass a stationary object of length b metres is the time taken by the train to cover (1 + b) metres.

 

5. Suppose two trains or two bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relatives speed = (u - v) m/s.

 

6. Suppose two trains or two bodies are moving in opposite directions at u m/s and v m/s, then their relative speed = (u + v) m/s.

 

7. If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then time taken by the trains to cross each other = (a+b)(u+v)sec.

 

8. If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then the time taken by the faster train to cross the slower train = a+bu-vsec.

 

9. If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then (A's speed) : (B’s speed) = b:a

Q:

To travel 432 km, an Express train takes 1 hour more than Duronto. If however, the speed of the Express train is increased by 50%, it takes 2 hours less than Duronto. What is the speed (in km/hr) of Duronto train?

A) 60 B) 54
C) 48 D) 72
 
Answer & Explanation Answer: B) 54

Explanation:
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4 2038
Q:

Train A can cross a man in 8 sec and a 180 m long platform ‘P’ in 17 sec. If train A cross train B which is running in opposite direction at speed of 108 km/hr in 8 sec, then find time taken by train B to cross platform P? 

A) 16 sec B) 11 sec
C) 14 sec D) 12 sec
 
Answer & Explanation Answer: C) 14 sec

Explanation:

Let length of train A be ‘L’ m and speed be ‘V’ m/s

ATQ –

V =

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3 2008
Q:

A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, the length of the train is

A) 90 m B) 100 m
C) 120 m D) 140 m
 
Answer & Explanation Answer: C) 120 m

Explanation:

Speed of the train = 12000 / 10*60 = 20 m/s

Length of the train = Speed X time = 20 X 6 = 120m

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2 1978
Q:

Excluding stoppages, the speed of a train is 120 kmph and including stoppages, it is 50 kmph. For how many minutes does the train stop per hour?

A) 25 B) 40
C) 35 D) 20
 
Answer & Explanation Answer: C) 35

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13 1876
Q:

To travel 732 km, an Express train takes 6 hours more than Rajdhani. If the speed of the Express train is doubled, it takes 3 hours less than Rajdhani. The speed of Rajdhani is

A) 81.3 km/hr B) 61 km/hr
C) 40.7 km/hr D) 101.7 km/hr
 
Answer & Explanation Answer: B) 61 km/hr

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1 1856
Q:

A train, starting from rest, attains a velocity of 90 kmph in 5 minutes. Assuming that the acceration is uniform, the distance travelled by the train during this time is

A) 1.5 km B) 2.25 km
C) 3.75 km D) 3.25 km
 
Answer & Explanation Answer: C) 3.75 km

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3 1744
Q:

Two trains move from stations M and N. Both trains move towards each other at speeds of 54 km/hr and 63 km/hr respectively. When they meeteach other, the second train has travel 100 km more than the first. What is the distance (in km) between M and N

A) 600 B) 700
C) 1300 D) 1500
 
Answer & Explanation Answer: C) 1300

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5 1738
Q:

A uniformly moving train of length 480 m takes 3 minutes to completely cross a platform. If the same train, with the same speed crosses a pole completely in 30 sec, then the length of the platform is -

A) 1 km B) 600 m
C) 4.8 km D) 1.2 km
 
Answer & Explanation Answer:

Explanation:

Let length of platform be ‘y’metres.

Then, at the platform,Distance travelled = y + (length of train) = (y + 480)m

Then, Speed of train = (y + 480)m / (3x60) sec = (y+480)/180 ...(1)

Also, at the pole,Distance travelled = length of train = 480m

Then, Speed of train = 480m / 30sec = 16 m/s ...(2)

Equating eq.(1) & eq.(2), we get,

(y+480)/180 = 16(y+480) = 16 x 180 = 2880

y = 2880 –480 = 2400m or 2.4 km long platform.

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2 1729