Q:
Average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 years, and B is 5 years younger to C, then find the difference between the age of A and C?
Answer & Explanation
Answer: B) 9
Explanation: Let the present ages of A & B to be ‘a’ & ‘b’ respectively.
Hence, 2 years ago, their ages must have been (a-2) & (b-2) respectively.
Average of their ages at that time = 26
Hence,
[(a-2)+(b-2)]/2 = 26
(a-2)+(b-2) = 52
a+b = 56
Age of A, 5 year hence = 40 years
Hence, (a+5) = 40
a = 35 years
Hence, b = 56 - 35 = 21 years
B = (C-5)
Hence, C = 21+5 = 26 years
Age difference between A & C = 35 - 26 = 9 years.
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