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 Problems on Ages Questions

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Q:

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A) E = 15 & Y = 3 B) E = 14 & Y = 12
C) E = 40 & Y = 22 D) E = 4 & Y = 2
 
Answer & Explanation Answer: D) E = 4 & Y = 2

Explanation:

Let the the age of the elder boy = E

 

Let the the age of the younger boy = Y

 

Given that Y = cube root of EY

 


=> Y3 = EY => E = Y2 .....(1)
By the condition of number replacement the age of the father is YE

 

The Mother's age = EY/2

 

But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)

 

Then now from the given options we can identify which satisfies the all the conditions.

 

Here Y =2 and E = 4 satisfies all the conditions.

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8 7372
Q:

Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?

A) 25 years B) 24 years
C) 23 years D) 22 years
 
Answer & Explanation Answer: C) 23 years

Explanation:

Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.

Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

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11 7249
Q:

The average of the ages of Sumit, Krishna and Rishabh is 43 years and the average of the ages of Sumit, Rishabh and Rohit is 49 years. If Rohit is 54 years old, what is Krishna'a age ? 

A) 48 yrs B) 42 yrs
C) 40 yrs D) 36 yrs
 
Answer & Explanation Answer: D) 36 yrs

Explanation:

Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , then
w+x+y = 43x3 = 129 ---(i) and
w+y+z = 49x3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)
Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36

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6 7190
Q:

If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ?

A) 22 yrs B) 21 yrs
C) 20 yrs D) 24 yrs
 
Answer & Explanation Answer: A) 22 yrs

Explanation:

Let Reena’s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.

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6 7167
Q:

The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago ?

A) 2 : 5 B) 8 : 15
C) 9 : 10 D) 3 : 5
 
Answer & Explanation Answer: C) 9 : 10

Explanation:

The ratio of X and Y ages at present is 4:5. 

Then, the ratio 20 years ago will not be more than the ratio at present.

So, from the options 9:10 is not satifying => its ratio is 0.9 which is greater than presnt ratio of 0.8.

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8 7152
Q:

The Age of Ashok , Deepak and Ramu are in the proportion of 3:5:6. If the difference between the ages of Deepak and Ramu is 5 years . what is Ashok's age in years?

Answer

Suppose the ages of Ashok, Deepak and Ramu are 3x, 5x and 6x years respectively.


   


Hence , Ashok's age =  =  = 15 years

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Subject: Problems on Ages

13 7109
Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years B) 72 years
C) 82 years D) 64 years
 
Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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6 7033
Q:

Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?

A) 20 B) 41
C) 26 D) 33
 
Answer & Explanation Answer: B) 41

Explanation:

Given P = 54 and M = 80

According to the question,

Let ‘A’ years ago, M = 3P

=> M - A/P - A = 3

=> 80 - A = 3(54 - A)

=> 80 - A = 162 - 3A

=> 2A = 82

=> A = 41

Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.

Hence, at the age S = 13 and M = 39.

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