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 Problems on Ages Questions

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Q:

Hari Ram’s present age is three times his son’s present age and two fifth of his father’s present age. The average of the present age of all of them is 46 years. What is the difference between Hari Ram’s son’s present age and Hari Ram’s father’s present age? 

A) 44 yrs B) 56 yrs
C) 67 yrs D) 78 yrs
 
Answer & Explanation Answer: D) 78 yrs

Explanation:

Let Hari Ram's present age = x

Then, his son's age = x/3

Father's age = 5x/2

x + x3 + 52x3 = 46=> x = 36 yrs

Now the required difference = 52x36 - 363 = 78 yrs

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11 8718
Q:

A man said to his son, "I was two-thirds of your present age when you were born". IIf the present age of the man is 48 years, find the present age of the son.

Answer

Let the Present age of the son be P, which means he was born P years ago.At the time the son was born, the age of the man was : (48 - P). So, according to the statement made by the man, his age when the son was born should be equal to 2/3 of P.


Therefore, 


Solving, we get P = 28.8 years; which is the present age of the son.

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Subject: Problems on Ages

10 8717
Q:

The ratio of Karthik’s and Kalyan’s ages is 4: 5. If the difference between the present age of Kalyan and the age of Karthik 5 years hence is 3 years, then what is the total of present ages of Karthik and Kalyan?

A) 56 years B) 62 years
C) 69 years D) 72 years
 
Answer & Explanation Answer: D) 72 years

Explanation:

Let us consider Karthik as K1 and Kalyan as K2.


Given k18+k1 and K2 - (K1 + 5) = 3 

K2 - K1 = 8

K2 = 8 + K1

Now, 

k18+k1= 45

=> K1 = 32 years

Therefore K2 = 40 years.

K1 + K2 = 72 years.

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7 8555
Q:

The average age of a couple was 26 years at the time of marriage. After 11 years of marriage, the average age of the family with 3 children become 19 years. The average age of the children is

Answer

The average age of a couple = 26 years.


Total age of couples = 26 x 2 = 52 years


 Total age of couple after 11 years = (52 + 2 * 11 ) = 74 years


Suppose average age of 3 children after 11 years is 3x years.



The average age of children is 7 years.

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Subject: Problems on Ages

10 8153
Q:

5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ?

A) 24 and 13 years B) 48 and 24 years
C) 35 and 11 years D) 33 and 15 years
 
Answer & Explanation Answer: C) 35 and 11 years

Explanation:

Let the age of sushma be x and
the age of her son is y
Then five years before x-5=5(y-5) ...(1)
Five years hence x+5 = 3(y+5)-8 .....(2)

By soving (1) & (2), we get
5y - 15 = 3y + 7
y = 11 => x = 35

Therefore, the age of Sushma = 35 and her son = 11.

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8 7905
Q:

Avanthi’s age is 1/6th of her father’s age. Her father’s age will be twice of Kapil’s age after 10 years. If Kapil’s eighth birthday was celebrated two years ago, then what is Avanthi’s present age ?

A) 6 years B) 4 years
C) 7 years D) None
 
Answer & Explanation Answer: D) None

Explanation:

As given Kapil's 8th birthday was celebrated 2 years ago,

Kapil’s present age = 8 + 2 = 10 years.

Father's age is twice of Kapil’s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,

Avanthi's age =1/6(F) = 30/6 = 5 years.

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10 7829
Q:

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A) E = 15 & Y = 3 B) E = 14 & Y = 12
C) E = 40 & Y = 22 D) E = 4 & Y = 2
 
Answer & Explanation Answer: D) E = 4 & Y = 2

Explanation:

Let the the age of the elder boy = E

 

Let the the age of the younger boy = Y

 

Given that Y = cube root of EY

 


=> Y3 = EY => E = Y2 .....(1)
By the condition of number replacement the age of the father is YE

 

The Mother's age = EY/2

 

But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)

 

Then now from the given options we can identify which satisfies the all the conditions.

 

Here Y =2 and E = 4 satisfies all the conditions.

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8 7764
Q:

Sum of present ages of P and Q is 41. Age of P 2 year hence is equal to age of R, 1 year ago. Age of P, 4 year hence is equal to age of Q 1 year ago and ratio of present age of P and S is 3 : 4. Find the difference of age of R and S. 

A) 2 B) 3
C) 4 D) 5
 
Answer & Explanation Answer: B) 3

Explanation:

According to the given data,

P + Q = 41 ......(1)

R - 1 = P + 2

R = P + 3

and

P + 4 = Q - 1

=> Q = P + 5 ....(2)

From (1)&(2)

P = 18

Q = 18 + 5 = 23

R = 18 + 3 = 21

=> P/S = 3/4

=> S = 4/3 x 18 = 24

Required Difference = S - R = 24 - 21 = 3.

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