Problems on Ages Questions

Q:

The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ?

A) 12 years B) 10 years
C) 14 years D) 13 years
 
Answer & Explanation Answer: A) 12 years

Explanation:

Given the average age of couple and their son = 40

=> Sum of age (H +W +S) = 40×3

Let the age of daughter in law at the time of marriage = D years

Now after 10 years,

(H + S +W) + 3×12 + D +12 + 10 = 38×5

178 + D = 190

D = 190 -178 = 12 years

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13 7129
Q:

12 year old Manish is three times as old as his brother Rajeev. How old will Manish be when he is twice as old as Rajeev ?

A) 12 yrs B) 14 yrs
C) 16 yrs D) 18 yrs
 
Answer & Explanation Answer: C) 16 yrs

Explanation:

12 year old Manish is three times as old as his brother Rajeev who must be 4 years old.
Diff in ages = 8 years.
when Rajeev will become 8 years old, Manish will be 16 yrs old and he will be twice as old as Rajeev.

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Q:

Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?

A) A is eldest & C is youngest B) D is eldest & C is youngest
C) C is eldest & A is youngest D) A is eldest & B is youngest
 
Answer & Explanation Answer: B) D is eldest & C is youngest

Explanation:

Given sum of present ages of A, B, C & D

A + B + C + D = 176

and also given that,

(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14

Let the ratio = x

=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x

=> (A + B + C + D ) - 16 = 40x

=> 176 - 16 = 40x

=> x = 4

=> A = 44 + 4 = 48

=> B = 40

=> C = 28

=> D = 60

Therefore, from the above conclusions

D is eldest with 60 years and C is youngest with 28 years of ages.

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Q:

Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ?

A) 18 years B) 21 years
C) 23 years D) 17 years
 
Answer & Explanation Answer: A) 18 years

Explanation:

At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x
12 years after:
Age of Sudeer = 4x+12
Age of Swetha = 3x+12
Now the equation is 3x+12=5/6(4x+12)
Solving equation we get x=6
Hence Swetha got married at the age of 18.

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Q:

Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ?

A) 36 years B) 28 years
C) 32 years D) 40 years
 
Answer & Explanation Answer: C) 32 years

Explanation:

Let Shilpa's present age is p years

According to question,

p = 4(x+4) – 4(x–4)

p = 4x+16 – 4x+16

p = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

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Q:

7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age?

A) 91 years B) 115 years
C) 103 years D) Can't be determined
 
Answer & Explanation Answer: C) 103 years

Explanation:

Let present Anirudh's age be 'A' and Bhavana's age be 'B'

Given seven years, their ratio is 7:9

=> A-7 : B-7 = 7 : 9

=> 9A - 7B = 14 .......(1)

And given,

Chandhu is 12 years older than A nad 12 years younger than B

=> C = A + 12....(2)

=> B = C + 12

=> B = A + 12 + 12 .....(From (2))

=> B = A + 24 ....(3)

Put (3) in (1)

9A - 7(A+24) = 14

9A - 7A - 168 = 14

2A = 182

=> A = 91 years

=> C = A + 12 = 91 +12 = 103 years.

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9 6515
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years 


Then B's age 10 years ago  be 2x yeats


\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}


\inline \Rightarrow 4(x+10)=3(2x+10)


\inline \Rightarrow x=5


\inline \therefore Total of their present ages =                                        


                                          = 


                                          = 35 years

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Subject: Problems on Ages

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Q:

Ishikha got married 9 years ago. Today her age is 4/3 times her age at the time of marriage. At present her daughter’s age is one-sixth of her age. What was her daughter’s age three years ago?

A) 4 years B) 3 years
C) 2 years D) 1 year
 
Answer & Explanation Answer: B) 3 years

Explanation:

Let Ishika and her daughter present ages be p and q

 From the given data, 

p = 4/3(p - 9)

 => p = 36 years 

Hence, Ishika's present age = 36 years and

Her daughter's present age = 1/6 x 36 = 6 years 

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

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