FACTS  AND  FORMULAE  FOR  PROBABILITY  QUESTIONS

 

 

1. Experiment : An operation which can produce some well-defined outcomes is called an experiment.

 

2. Random Experiment :An experiment in which all possible outcomes are know and the exact output cannot be predicted in advance, is called a random experiment.

Ex :

i. Tossing a fair coin.

ii. Rolling an unbiased dice.

iii. Drawing a card from a pack of well-shuffled cards.

 

3. Details of above experiments:

i. When we throw a coin, then either a Head (H) or a Tail (T) appears.

ii. A dice is a solid cube, having 6 faces, marked 1, 2, 3, 4, 5, 6 respectively. When we throw a die, the outcome is the number that appears on its upper face.

iii. A pack of cards has 52 cards.

  • It has 13 cards of each suit, name Spades, Clubs, Hearts and Diamonds.
  • Cards of spades and clubs are black cards.
  • Cards of hearts and diamonds are red cards.

There are 4 honours of each unit. There are Kings, Queens and Jacks. These are all called face cards.

 

4. Sample Space: When we perform an experiment, then the set S of all possible outcomes is called the sample space.

Ex :

1. In tossing a coin, S = {H, T}

2. If two coins are tossed, the S = {HH, HT, TH, TT}.

3. In rolling a dice, we have, S = {1, 2, 3, 4, 5, 6}.

Event : Any subset of a sample space is called an event.

 

5. Probability of Occurrence of an Event : 

Let S be the sample and let E be an event.

Then, ES

P(E)=n(E)n(S)

6. Results on Probability :

i. P(S) = 1    ii. 0P(E)1   iii. P()=0

 

iv. For any events A and B we have : 

P(AB)=P(A)+P(B)-P(AB)

 

v. If A denotes (not-A), then P(A)=1-P(A)

Q:

If the difference between the mode and median is 2, then the difference between the median and mean is:

A) 2 B) 1
C) 3 D) 4
 
Answer & Explanation Answer: B) 1

Explanation:
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33 3559
Q:

Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 1/5 B) 1/7
C) 1/6 D) 1/9
 
Answer & Explanation Answer: C) 1/6

Explanation:

Out of 9 persons,4 can be choosen in 9C4 ways =126.

 

Favourable events for given condition = 2C2*7C2= 21.

 

So,required probability = 21/126 =1/6.

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1 3548
Q:

A five digit number is formed with the digits 0,1,2,3 and 4 without repetition. Find the chance that the number is divisible by 5.

A) 3/5 B) 1/5
C) 2/5 D) 4/5
 
Answer & Explanation Answer: B) 1/5

Explanation:
5 digit number = 5! = 120
Divisible by 5 then the last digit should be 0
Then the remaining position have the possibility = 4!
= 24
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25 3365
Q:

From well shuffled standard pack of 52 playing cards,one card is drawn. What is the probability that it is either a red card or black card?

A) 1/2 B) 3/4
C) 1 D) 1/3
 
Answer & Explanation Answer: C) 1

Explanation:

P(red cards)=26/52

P(black cards)=26/52

P(red or black cards)=26/52+26/52=1

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1 3145
Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3 B) 1/2
C) 1/4 D) 1/6
 
Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

 

There are 26 red cards,out of which one red card can be drawn in 26C1 ways =26.

 

So,required probability = 26/52 = 1/2

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3 3145
Q:

In a single throw with 2 dices, what is probability of neither getting an even number on one and nor a multiple of 3 on other?

A) 11/36 B) 25/36
C) 5/6 D) 1/6
 
Answer & Explanation Answer: B) 25/36

Explanation:

We first calculate the probability of getting an even number on one and a multiple of 3 on other,Here, n(s) = 6x6 = 36 and

E = (2,3) (2,6) (4,3) (4,6) (6,3) (6,6) (3,2) (3,4)(3,6) (6,2)(6,4)

n(E) = 11P(E) = 11/36Required probability = 1-11/36 = 25/36

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16 2913
Q:

Find the probability that one ball is white when two balls are drawn at random from a basket that contains 9 red, 7 white and 4 black balls.

A) 18/95 B) 18/190
C) 1/2 D) 91/190
 
Answer & Explanation Answer: D) 91/190

Explanation:

Total number of elementary events = 20C2 ways =190

 

There are 7 white balls out of which one white can be drawn in 7C1 ways and one ball from remaining 13 balls can be drawn in 13C1 ways.

 

So,favourable events = 7C1*13C1

 

Therfore,required probability = (7C1*13C1)/20C2=91/90

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2 2885
Q:

Find the range and mode of the data 17, 18, 28, 19, 16, 18, 17, 29, 18

A) 12 and 18 B) 13 and 18
C) 12 and 17 D) 11 and 17
 
Answer & Explanation Answer: B) 13 and 18

Explanation:
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