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Q:

There is a 3 digited number. 3rd digit is the square root of the 1st digit. 2nd digit is the sum of 1st and 3rd. And that number is divisible by 2,3,6,7. What is that number?

A) 121 B) 943
C) 462 D) None
 
Answer & Explanation Answer: C) 462

Explanation:

Assume that the number is taken as XYZ.
Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9
Condition 2 => Y = X + Z
X Y Z
1 2 1
4 6 2
9 12 3 => (wrong because it is 4 digit.)

and 121 is not divisible by 2

The answer is 462.

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3 3984
Q:

Find the remainder when 629 is divided by 5 ?

A) 0 B) 1
C) 3 D) 5
 
Answer & Explanation Answer: B) 1

Explanation:

All powers of 6 has 6 in units place so answer will definitely be 1.

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4 3958
Q:

There are four consecutive even integers. Sum of the reciprocals of the first two number is (11/60). Find the reciprocal of third largest number of the series.

A) 1/12 B) 2/14
C) 1/14 D) 2/13
 
Answer & Explanation Answer: C) 1/14

Explanation:

Ans. C.
Let 4 consecutive even numbers are x, x+ 2, x+ 4, x+ 6
According to the question -
1/x + 1/x+2 = 11/60
x+2+x/ x(x+2) = 11/60
2(x+1)/x^2 + 2x = 11/60
120x + 120 = 11x 2 + 22x
11x 2 - 98x – 120 = 0
So ,
X = -24/22 , 10
X = -12/11 , 10
So, the numbers will be 10,12,14,16.
Hence,
Third largest number = 14
Reciprocal of third number = 1/14

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2 3825
Q:

Find the next number in the series 2, 3, 4, 8, 9, 10, 11, 16, 17, 18, 19, 20,...

A) 27 B) 26
C) 24 D) 25
 
Answer & Explanation Answer: B) 26

Explanation:

The pattern is three consecutive numbers and then three consecutive numbers missing.Then four consecutive numbers and then four consecutive numbers missing.Then five consecutive numbers and then five consecutive numbers missing.

 

The next number=20+6=26

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8 3815
Q:

If you write down all the numbers from 1 to 100, then how many times do you write 4 ?

A) 11 B) 20
C) 17 D) 14
 
Answer & Explanation Answer: B) 20

Explanation:

4, 14, 24, 34, 44, 54, 64, 74, 84, 94 => has 11 number of (4's)
40, 41, 42, 43, 45, 46, 47, 48, 49 => has 9 number of (4's)
So, totally (11 + 9 = 20) number of 4's in 1 to 100.

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2 3731
Q:

 7, 16, 36, 78, 144, ?

which number come in place of question mark

A) 168 B) 196
C) 222 D) 256
 
Answer & Explanation Answer: C) 222

Explanation:
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43 3531
Q:

How many prime numbers exist in 65×359×113 ?

A) 29 B) 31
C) 33 D) 27
 
Answer & Explanation Answer: B) 31

Explanation:

Given  65×359×113

⇒2×35×5×79×113 

⇒25×35×59×79×113

Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.

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5 3427
Q:

If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: D) 0

Explanation:

Let assume the value of a,b &c that will satisfy the equation.
so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1
here all three cases satisfy the equation
assume any one a=1,b=1,c= -1

Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0

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5 3385