Q:

A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ?

A) 10.5 kgs B) 12 kgs
C) 9.6 kgs D) 11.5 kgs
 
Answer & Explanation Answer: D) 11.5 kgs

Explanation:

Screws weight = 90x100 = 9000gms
bolts weight = 100 x 150 = 15000gms
weight = screws + bolts => 24000 gms =>24 kg
Given entire box weight = 35.5kg
empty box = entire box weight - weight => 35.5kg - 24kg => 11.5kg
so the empty box is 11.5kg.

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8 7164
Q:

934+7217-9115=?

A) 7 + 719/1020 B) 9 + 817/1020
C) 9 + 719/1020 D) 7 + 817/1020
 
Answer & Explanation Answer: D) 7 + 817/1020

Explanation:

given sum =9+34+7+217-9+115

 

9+7+9+34+217-115

 

=> 7+765+120-681020=>7+8171020 

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4 7042
Q:

Which number will fit in '?' place in the following series?

 

12, 23, 45, 89, ?

 

A) 175 B) 176
C) 177 D) 178
 
Answer & Explanation Answer: C) 177

Explanation:
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9 6792
Q:

What will be the 20th term in the given sequence?

 

-50, -47, -44, _

 

A) -10 B) 10
C) -7 D) 7
 
Answer & Explanation Answer: D) 7

Explanation:
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10 6581
Q:

About 4 out of 5 students are left handed. If there are totally 40 students in an class. How many would be left handed ?

A) 40 B) 45
C) 32 D) 30
 
Answer & Explanation Answer: C) 32

Explanation:

Probability of left handed = 4/5
total student = 40
total left handed = 40 x(4/5)
= 32

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12 6428
Q:

A teacher multiplies 987 by a certain number and obtains 556781 as her answer. If in the answer, both 6 and 7 are wrong but the other digits are correct, then the correct answer will be

A) 553681 B) 555181
C) 556581 D) 555681
 
Answer & Explanation Answer: D) 555681

Explanation:

Given number is 987 = 3 x 7 x 47.

So, required number must be divisible by each one of 3, 7, 47.

None of the numbers in 553681 and 555181 are divisible by 3. While 556581 is not divisible by 7.
Correct answer is 555681.

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6 6259
Q:

The difference of two numbers is 11 and (1/5)th of their sum is 9. The numbers are

Answer

Let the numbers be x and (x-11)



\inline \fn_jvn \Rightarrow   x = 28


\inline \fn_jvn \therefore Another Number is (28 - 11) = 17

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Subject: Numbers

14 6148
Q:

In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ?

A) 138 to 164 B) 125 to 147
C) 148 to 158 D) 152 to 164
 
Answer & Explanation Answer: D) 152 to 164

Explanation:

A+7B=112

it is clear that A = 14, then it becomes A>=B, but A is smallest angle) given
so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)

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8 6013