Compound Interest Questions

FACTS  AND  FORMULAE  FOR  COMPOUND  INTEREST  QUESTIONS

 

 

Let Principal = P, Rate = R% per annum, Time = n years.

I.

1.  When interest is compound Annually:

Amount =P1+R100n

2.  When interest is compounded Half-yearly:

Amount = P1+(R2)1002n

3.  When interest is compounded Quarterly:

Amount = P1+R41004n

 

II.

1.  When interest is compounded Annually but time is in fraction, say 325 years.

Amount = P1+R1003×1+25R100

2.  When Rates are different for different years, say R1%, R2%, R3% for 1st, 2nd and 3rd year respectively.

Then, Amount = P1+R11001+R21001+R3100

 

III.  Present worth of Rs. x due n years hence is given by:

Present Worth = x1+R100n

Q:

The compound interest on Rs. 8000 for 3 year at 10% p.a. is

A) 2648 B) 2145
C) 2587 D) 2784
 
Answer & Explanation Answer: A) 2648

Explanation:

8000 × 33.1% = 2648

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18 4258
Q:

Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years?

A) Rs. 704 B) Rs. 854
C) Rs. 893 D) Rs. 914
 
Answer & Explanation Answer: A) Rs. 704

Explanation:

We know that,

S.I. = PTR100 P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1

From given data, P = Rs. 8625

Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

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11 4233
Q:

For S = $21,000, payments (R) of $1500 at the end of each 6-month periodi= 10% compounded semi-annually. Find the minimum number of payments to accumulate 21,000.

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

S=R[(1+i)^n-1)/i]

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0 4116
Q:

Two payments of $10,000 each must be made one year and four years from now. If money can earn 9% compounded monthly, what single payment two years from now would be equivalent to the two scheduled payments?

A) 17296 B) 13296
C) 19296 D) 15296
 
Answer & Explanation Answer: C) 19296

Explanation:

i=j/m

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1 4061
Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A) 3years B) 2years
C) 4years D) 6years
 
Answer & Explanation Answer: B) 2years

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000*(1+7/100)^n=34347

n= 2 years

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0 4054
Q:

A loan is made for $4800 with an APR of 12% and payments made monthly for 24 months. What is the payment amount? What is the finance charge?

A) 622.80 B) 522.80
C) 322.80 D) 632.80
 
Answer & Explanation Answer: A) 622.80

Explanation:

{\color{Blue} A=R\left [(1+i)^{n-1} \right ]/i ( 1+i )^{n}}

 

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0 4018
Q:

Example:Given an amount needed(future value) of $3300 in 4 years at an interest rate of 11% compounded anually,Find the present value and the amount of interest earned

A) 1126.19 B) 1237
C) 2863 D) 1892
 
Answer & Explanation Answer: A) 1126.19

Explanation:

M=P(1+i)^n

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0 4016
Q:

Kashundra Jones plans to make a lump sum deposit so that she can withdraw $3,000 at the end of each quarter for 10 years. Find the lump sum if the money earns 10% per year compounded quarterly

A) 75263.64 B) 76345
C) 76389 D) 56897
 
Answer & Explanation Answer: A) 75263.64

Explanation:

 

 

A=R[(1+i)^n-1]/i(1+i)^n

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0 3948