Compound Interest Questions

FACTS  AND  FORMULAE  FOR  COMPOUND  INTEREST  QUESTIONS

 

 

Let Principal = P, Rate = R% per annum, Time = n years.

I.

1.  When interest is compound Annually:

Amount =P1+R100n

2.  When interest is compounded Half-yearly:

Amount = P1+(R2)1002n

3.  When interest is compounded Quarterly:

Amount = P1+R41004n

 

II.

1.  When interest is compounded Annually but time is in fraction, say 325 years.

Amount = P1+R1003×1+25R100

2.  When Rates are different for different years, say R1%, R2%, R3% for 1st, 2nd and 3rd year respectively.

Then, Amount = P1+R11001+R21001+R3100

 

III.  Present worth of Rs. x due n years hence is given by:

Present Worth = x1+R100n

Q:

Jackie deposits $325 in an account that pays 4.1% interest compounded annually. How much money will Jackie have in her account after 3 years?

A) 346.64 B) 356.64
C) 366.64 D) 376.64
 
Answer & Explanation Answer: C) 366.64

Explanation:

A=P(1+r)^t

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0 4677
Q:

Kramer borrowed $4000 from George at an interest rate of 7% compounded semiannually. The loan is to be repaid by three payments. The first payment, $1000, is due two years after the date of the loan. The second and third payments are due three and five years, respectively, after the initial loan. Calculate the amounts of the second and third payments if the second payment is to be twice the size of the third payment.

A) 1389 B) 1359
C) 1379 D) 1339.33
 
Answer & Explanation Answer: D) 1339.33

Explanation:

Given:j=7% compounded semiannually making m=2 and i = j/m= 7%/2 = 3.5%
Let x represent the third payment. Then the second payment must be 2x.
PV1,PV2, andPV3 represent the present values of the first, second, and third payments.

Since the sum of the present values of all payments equals the original loan, then
PV1 + PV2  +PV3  =$4000 -------(1)

PV1   =FV/(1 + i)^n  =$1000/(1.035)^4=  $871.44

At first, we may be stumped as to how to proceed for
PV2 and PV3. Let’s think about the third payment of x dollars. We can compute the present value of just $1 from the x dollars

pv=1/(1.035)^10=0.7089188

PV2   =2x * 0.7089188 = 1.6270013x
PV3   =x * 0.7089188=0.7089188x
Now substitute these values into equation ➀ and solve for x.
$871.442 + 1.6270013x + 0.7089188x  =$4000

2.3359201x  =$3128.558

x=$1339.326
Kramer’s second payment will be 2($1339.326)  =$2678.65, and the third payment will be $1339.33

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0 4580
Q:

Mr. and Mrs. Espedido’s property taxes, amounting to $2450, are due on July 1.What amount should the city accept if the taxes are paid eight months in advance and the city can earn 6% compounded monthly on surplus funds?

A) 2354.17 B) 2354
C) 2376 D) 2389
 
Answer & Explanation Answer: A) 2354.17

Explanation:

i=j/m

PV=  FV(1+  i)^-n 

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Q:

What periodic payment will an investor receive from a $9000, four-year, monthly payment GIC earning a nominal rate of 5.25% compounded monthly?

A) 29.38 B) 39.38
C) 49.38 D) 59.38
 
Answer & Explanation Answer: B) 39.38

Explanation:

i=j/m

The monthly payment will be=PV*I

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Q:

The effective annual rate of interest corresponding to nominal rate of 6% per annum payable half yearly is

A) 5% B) 6%
C) 7% D) 6.09%
 
Answer & Explanation Answer: D) 6.09%

Explanation:

amount=[100(1+3/100)^2]=Rs.106.09

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1 4446
Q:

A sum is equally invested in two different schemes on CI at the rate of 15% and 20% for two years. If interest gained from the sum invested at 20% is Rs. 528.75 more than the sum invested at 15%, find the total sum?

A) Rs. 7000 B) Rs. 4500
C) Rs. 9000 D) Rs. 8200
 
Answer & Explanation Answer: C) Rs. 9000

Explanation:

Let Rs. K invested in each scheme

Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%

Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%

Now,

(P x 44/100) - (P x 32.25/100) = 528.75

=> 11.75 P = 52875

=> P = Rs. 4500

 

Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.

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Q:

What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly?

A) Rs. 1.80 B) Rs. 2.04
C) Rs. 3.18 D) Rs. 4.15
 
Answer & Explanation Answer: B) Rs. 2.04

Explanation:

Compound Interest for 1 12 years when interest is compounded yearly = Rs.(5304 - 5000)


Amount after 112 years when interest is compounded half-yearly 


Compound Interest for 1 12 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)


Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

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Q:

Sharon Stone deposits $2000 at the end of each year in an account earning 10% compounded annually. Determine how much money she has after 25 years. How much interest did she earn?

A) 146694.12 B) 13452
C) 18232 D) 15627
 
Answer & Explanation Answer: A) 146694.12

Explanation:

S=R[(1+i)^n-1]/i

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