Questions

The paste applied to the side of a match box is a mixture of phosphorus trisulphide, glass powder (or sand) to cause friction and glue (binding material)

#include "mem.h"

#include "alloc.h"

main()

{

      int area;

      char *dest;

      char src[] = "Life is the camera and you are the target"

                                  "so keep smiling always";

      area = sizeof (src);

      dest = malloc (area);

      memmove (dest, src, area);

      printf("\n%s", dest);

      printf("\n%s",src);

}

The given math puzzle follows a logic that,

1 + 4 = 5 => 1 x 4 + 1 = 5

2 + 5 = 12 => 2 x 5 + 2 = 12

3 + 6 = 21 => 3 x 6 + 3 = 21

Similarly,

8 + 11 = > 8 x 11 + 8 = 96.

At least one black can be chosen in two ways from each box:
Now, probability of choosing at least one black ball from first box 

= 1/2 × [ (2C1× 2C1)/4C2 + 2C2/ 4C2 ]= 5/12

Probability of choosing at least one black ball from 2nd box
= 1/2 × [(4C1×12C1)/16C2 + 4C2/ 16C2] = 9/40

Final probability

= 5/12 + 9/40 = (50 + 27)/120 = 77/120

RST0, RST1, RST2, RST3, RST4, RST5, RST6, RST7.