Q:
Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?
Answer & Explanation
Answer: B) 2k1k2/k1+k2
Explanation: We know that,
The equivalent K =
where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively.
But here L1 = L2 = L (say)
Then K = L+L/(L/K1 + L/K2) =
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