Questions

Q:

Which of the following crop is known as Green Gold?

A) Coffee B) Neem
C) Tea D) Rice
 
Answer & Explanation Answer: C) Tea

Explanation:

Tea crop is known as Green Gold.

Report Error

View Answer Report Error Discuss

Filed Under: General Science
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

11 7097
Q:

 When three or more AND and OR conditions are combined, it is easier to use the SQL keyword(s):

A) LIKE only. B) IN only.
C) NOT IN only. D) Both IN and NOT IN.
 
Answer & Explanation Answer: D) Both IN and NOT IN.

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Database

2 7093
Q:

Milk is an example of a

A) Emulsion B) Solution
C) Gel D) Suspension
 
Answer & Explanation Answer: A) Emulsion

Explanation:

Milk is an emulsion of oil in water (o/w).


Emulsion: A suspension of droplets of one liquid in another.

Constituents of milk :

The principal constituents of milk are water, fat, proteins, lactose (milk sugar) and minerals (salts). Milk also contains trace amounts of other substances such as pigments, enzymes, vitamins, phospholipids (substances with fatlike properties), and gases.

Report Error

View Answer Report Error Discuss

Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

10 7092
Q:

According to ohm's law, which of the following is true?

 

A) The current flowing through a wire is directly proportional to the Potential Difference applied across its ends B) The current flowing through a wire is directly proportional to its resistance
C) The current flowing through a wire is indirectly proportional to its length D) The current flowing through the wire is indirectly proportional to the Potential Difference applied across its ends  
 
Answer & Explanation Answer: A) The current flowing through a wire is directly proportional to the Potential Difference applied across its ends

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Physics
Exam Prep: Bank Exams

0 7089
Q:

The Narmada river originates in _______

A) Vindhyan Range B) Maikal Range
C) Satpura Range D) Mahadeo Range
 
Answer & Explanation Answer: B) Maikal Range

Explanation:

It rises on the Amarkantak plateau in the in the Maikal Range from a spring at a height of 1060m

Report Error

View Answer Report Error Discuss

Filed Under: Indian Geography

11 7086
Q:

What does one mole of H2O correspond to

A) 16 gms B) 18 gms
C) 20 gms D) 22 gms
 
Answer & Explanation Answer: B) 18 gms

Explanation:

The molar mass of H2O can be calculated as the following.

M(H2O)= [2 x M(H)] + [M(O)].

And we know that M(H) = 1g/mol, M(O) = 16g/mol.

So, M(H2O)= 2x1 + 16 = 18g/mol,

That means 1 mole of H2O contains 18g.

 

Hence, one mole of H2O corresponds to 18 grams.

Report Error

View Answer Report Error Discuss

Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

6 7081
Q:

Which state government has launched e-health program “Jeevan Rekha” to provide a centralised database of healthcare information? 

A) Assam B) Kerala
C) Madhya Pradesh D) Chhattisgarh
 
Answer & Explanation Answer: B) Kerala

Explanation:

The C.M of Kerala, Pinarayi Vijayan has recently launched e-health program “Jeevan Rekha” to make electronic health records of a population in Thiruvananthapuram.

 

It is a first-of-its-kind initiative in India to provide a centralised database of healthcare information and efficient service delivery to the people.

 

The new system would help in creating a good hospital management system and patient-friendly atmosphere in hospitals.

 

Once data of a patient is centralised, it would help the person get continuous treatment at all hospitals in the state.

Report Error

View Answer Report Error Discuss

Filed Under: General Awareness

43 7080
Q:

In the following pieces of code, B and D will compile without any error. True or false ?

A: StringBuffer sb1 = "abcd";

B: Boolean b = new Boolean("abcd");

C: byte b = 255;

D: int x = 0x1234;

E: float fl = 1.2;

A) TRUE B) FALSE
Answer & Explanation Answer: A) TRUE

Explanation:

The code segments B and D will compile without any error. A is not a valid way to construct a StringBuffer, you need to create a StringBuffer object using "new". B is a valid construction of a Boolean (any string other than "true" or "false" to the Boolean constructor will result in a Boolean with a value of "false"). C will fail to compile because the valid range for a byte is -128 to +127 (i.e., 8 bits, signed). D is correct, 0x1234 is the hexadecimal representation in java. E fails to compile because the compiler interprets 1.2 as a double being assigned to a float (down-casting), which is not valid. You either need an explicit cast, as in "(float)1.2" or "1.2f", to indicate a float.

Report Error

View Answer Workspace Report Error Discuss

6 7079