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 Alligation or Mixture Questions

Popular Latest Rated Important Formulae

FACTS  AND  FORMULAE  FOR  ALLIGATION  OR  MIXTURE  QUESTIONS

 

 

I. Alligation : It is the rule that enables us to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture of a desired price.

 

II. Mean Price : The cost price of a unit quantity of the mixture is called the mean price.

 

III. Rule of Alligation : Suppose Rs.x per unit be the price of first ingradient mixed with another ingradient (cheaper) of price Rs.y per unit to form a mixture whose mean price is Rs. z per unit, then 

Quantity of cheaper : Quantity of dearer

       = ( C.P of dearer - Mean Price ) : ( Mean Price - C. P of cheaper )

       = ( x- z ) : ( z - y )

 

 IV. Suppose a container contains x units of liquid from which y units are taken out and replaced by water. After  operations , the quantity of pure liquid = x1-yxn units.

 

Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

A) 2:3 B) 4:3
C) 3:4 D) 3:2
 
Answer & Explanation Answer: D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

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17 5414
Q:

Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him ?

A) 15.84 B) 14.92
C) 13.98 D) 16.38
 
Answer & Explanation Answer: D) 16.38

Explanation:

Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg.

Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25)

=> Total cost of the mixture = Rs. 630

Total kgs of the mixture = 30 + 20 = 50kg

Cost of mixture/kg = 630/50 = 12.6/kg

To make 30% of profit

=> Selling price for manideep = 12.6 + 30% x 12.6

=> Selling price for manideep = 12.6 + 3.78 = 16.38/kg.

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11 4306
Q:

A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ?

A) 88.01 lit B) 87.48 lit
C) 87.51 lit D) 87.62 lit
 
Answer & Explanation Answer: B) 87.48 lit

Explanation:

For these type of problems,

Quantity of Diesel remained = q1-pqn   

 

Here p = 12 , q = 120 

 

=> 1201-121203 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

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14 4239
Q:

The ratio of milk to water is 5:4. If two litres of water is added, the ratio becomes 10:9, then find the new amount of water in the mixture.

A) 12 litres B) 14 litres
C) 16 litres D) 17 litres
 
Answer & Explanation Answer:

Explanation:

Let initial quantity of milk & water in the mixture are 5x & 4x
2 litres water is added.
Hence,
New quantity of milk & water will be 5x & (4x+2)
ATQ,
5x/(4x+2) = 10/9
x/(4x+2) = 2/9 9x = 8x + 4
x=4
Hence,
New amount of water in the mixture = 4x+2 = (4*4) + 2 = 18 litres.

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2 4123
Q:

Shiva purchased 280 kg of Rice at the rate of 15.60/kg and mixed it with 120 kg of rice purchased at the rate of 14.40/kg. He wants to earn a profit of Rs. 10.45 per kg by selling it. What should be the selling price of the mix per kg?

A) Rs. 22.18 B) Rs. 25.69
C) Rs. 26.94 D) Rs. 27.54
 
Answer & Explanation Answer: B) Rs. 25.69

Explanation:

Rate of rice of quantity 280 kg = Rs. 15.60/kg

Rate of rice of quantity 120 kg = Rs. 14.40/kg

He want to earn a profit of Rs. 10.45/kg

Rate of Mix to sell to get profit of 10.45 =  

 

280 x 15.60 + 120 x 14.40280 + 120 + 10.454368 + 1728400 + 10.45=> 15.24 + 10.45= 25.69 

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12 4080
Q:

A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, the profit % ?

A) 22.5% B) 25%
C) 20% D) 33.33%
 
Answer & Explanation Answer: B) 25%

Explanation:

As water costs free, water sold at cost price of milk gives the profit.

Required profit % = 5/20 x 100 = 5 x 5 = 25%.

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19 3608
Q:

In a mixture of 60 litres, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?

A) 42 Litres B) 56 Litres
C) 60 Litres D) 77 Litres
 
Answer & Explanation Answer: C) 60 Litres

Explanation:

Ratio of milk and water = 2 : 1
Quantity of milk = 60 X 2/3 = 40 litre
Quantity of water = 20 litre
To make ratio, 1: 2, we have to double the water that of milk
So, water should be 80 litre.
That means 80 – 20 = 60 litre water to be added.

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3 3490
Q:

From container A containing 54 liter of mixture of milk and water in ratio of 8 : 1 , 18 liter of the mixture is taken out and poured into container B in which ratio of milk to water is 3 : 1. If difference between total milk and total water in container B is 30 liter then find the quantity of initial mixture in container B. 

A) 30 Liter  B) 28 Liter 
C) 32 Liter  D) 36 Liter 
 
Answer & Explanation Answer: C) 32 Liter 

Explanation:

Let initially milk and water in container B is 3x liter and x liter respectively

Now, 3x + (8/9) × 18 – x – (1/9) × 18 = 30

3x + 16 – x – 2 = 30

x = 8

Initial quantity is container B = 8 (3 + 1) = 32 Liter.

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7 3398