320+ Time and Distance Problems With Solutions And Explanation

Q:

A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ?

A) 85 km/hr	B) 95 km/hr
C) 105 km/hr	D) 120 km/hr

Answer & Explanation Answer: D) 120 km/hr

Explanation:

Initial speed = 80km/hr
Total distance = 80 x 10 = 800km
New speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

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Q:

Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ?

A) 20 kmph	B) 18 kmph
C) 12 kmph	D) 16 kmph

Answer & Explanation Answer: C) 12 kmph

Explanation:

Let the distance traveled be x km.
Then, x/10 - x/15 = 2
3x - 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.

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Q:

Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?

A) 1102 km	B) 1060 km
C) 960 km	D) 1250 km

Answer & Explanation Answer: C) 960 km

Explanation:

60(x + 1) = 64x

X = 15

60 x 16 = 960 km

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Q:

A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?

A) 55 kmph	B) 58 kmph
C) 60 kmph	D) 66 kmph

Answer & Explanation Answer: C) 60 kmph

Explanation:

Speed on return trip = 150% of 50 = 75 km/hr.

Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

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Q:

A train covers 180 km distance in 5 hours. Another train covers the same distance in 1 hour less. What is the difference in the distances covered by these trains in one hour if they are moving in the same direction?

A) 15 kms	B) 9 kms
C) 6 kms	D) 18 kms

Answer & Explanation Answer: B) 9 kms

Explanation:

The first train covers 180 kms in 5 hrs

=> Speed = 180/5 = 36 kmph

Now the second train covers the same distance in 1 hour less than the first train => 4 hrs

=> Speed of the second train = 180/4 = 45 kmph

Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.

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Q:

Mr. Karthik drives to work at an average speed of 48 km/hr. Time taken to cover the first 60% of the distance is 20 minutes more than the time taken to cover the remaining distance. Then how far is his office ?

A) 40 km	B) 50 km
C) 70 km	D) 80 km

Answer & Explanation Answer: D) 80 km

Explanation:

Let the total distance be 'x' km.

Time taken to cover remaining 40% of x distance is $t 1 = \frac{40 \times x}{100 \times 48}$

But given time taken to cover first 60% of x distance is $t 2 = t 1 + \frac{20}{60} h r s$

$t 2 = \frac{60 \times x}{100 \times 48}$

$∴ \frac{60 \times x}{100 \times 48} = \frac{40 \times x}{100 \times 48} + \frac{20}{60}$

x=80 km.

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Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Q:

The respective ratio between the speed of a bike, a van and lorry is 3 : 5 : 2. The speed of the van is 250 percent of the speed of the lorry which covers 360 km in 12 hours. What is the average speed of the bike and the van together?

A) 60 kmph	B) 62 kmph
C) 64 kmph	D) 63 kmph

Answer & Explanation Answer: A) 60 kmph

Explanation:

Speed of lorry = $\frac{360}{12}$ = 30 kmph

Speed of van = $\frac{250}{100} x 30$ = 75 kmph

Speed of bike = $\frac{3}{5} x 75$ = 45 kmph

Therefore, now required average speed of bike and van = $\frac{75 + 45}{2}$ = 60 kmph.

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