Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If x2+ x = 19, then what is the value of (x + 5)2+ [1/(x + 5)2]?

A) 77 B) 79
C) 81 D) 83
 
Answer & Explanation Answer: B) 79

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Q:

XYZ is right angled at Y. If tanX = 24/7, then what is the value of cotZ ?

A) 25/7 B) 24/25
C) 7/24 D) 24/7
 
Answer & Explanation Answer: D) 24/7

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Q:

If p/q = (x+3)/(x-3), then what is the value of p2+q2p2-q2 ?

A) x+9 B) x2+96x
C) x2+186x D) 0
 
Answer & Explanation Answer: B) x2+96x

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Q:

If a = 73, b = 74 and c = 75, then what is the value of a3 + b3 + c3  3abc?

A) 365 B) 444
C) 666 D) 999
 
Answer & Explanation Answer: C) 666

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Q:

If 1/3(12x/5 - 1/2) + 6/5 = 7/6, then what is the value of x?

A) 1/6 B) -1/6
C) 1/5 D) -1/5
 
Answer & Explanation Answer: A) 1/6

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Q:

For x = 462+3, what is the value of x+22x-22+x+23x-23

A) 1 B) √2
C) √3 D) 2
 
Answer & Explanation Answer: D) 2

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Q:

P is a point outside the circle at distance of 6.5 cm from centre O of the circle. PR be a secant such that it intersects the circle at Q and R. If PQ = 4.5 cm and QR = 3.5 cm, then what is the radius (in cm) of the circle?

A) 1.5 B) 2
C) 2.5 D) 3
 
Answer & Explanation Answer: C) 2.5

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Q:

If cot2A = x, then x is

A) 2cotA/(cot2A -­ 1) B) (cot2A -­ 1)/2cotA
C) (cot2A + 1)/2cotA D) 2cotA/(1 -­ cot2A)
 
Answer & Explanation Answer: B) (cot2A -­ 1)/2cotA

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