Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If a2+b2+c2=83 and a+b+c=15 then the value of ab+bc+ca is

A) 69 B) 70
C) 71 D) 72
 
Answer & Explanation Answer: C) 71

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Q:

If a2+b2=80 and ab = 32, then calculate the value of a-b/a+b.

A) 0.337 B) 0.339
C) 0.333 D) 0.335
 
Answer & Explanation Answer: C) 0.333

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Q:

The value of cosec260 + sec260  cot260 + tan230 will be

A) 5 B) 5 1/2
C) 5 1/3 D) 5 2/3
 
Answer & Explanation Answer: C) 5 1/3

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Q:

If x + y = 12 and xy = 32, then what is the value of  x2 + y2 ?

A) 24 B) 144
C) 128 D) 80
 
Answer & Explanation Answer: D) 80

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Q:

If x3+ 2x2 5x + k is divisible by x + 1, then what is the value of k?

A) -6 B) -1
C) 0 D) 6
 
Answer & Explanation Answer: A) -6

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Q:

If x + 1x = c + 1c, then the value of x =

A) C, 1/C B) C, C2
C) C, 2C D) 0,1
 
Answer & Explanation Answer: A) C, 1/C

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Q:

If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2 )

A) b2-a2+2c2b2+a2 B) b2+a2-2c2b2-a2
C) b2-a2-2c2b2+a2 D) b2-a2b2+a2+2c2
 
Answer & Explanation Answer: B) b2+a2-2c2b2-a2

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Q:

Sum of cubes of first n even natural numbers.

Answer

Proof of Sum of cubes of first n even natural numbers ::


sum_of_cubes_of_first_n_even_natural_numbers1556603651.png image


 


Hence, in other words, the sum of the first n cubes is the square of the sum of the first n natural numbers.

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