Q:
      
      
         
            
Average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 years, and B is 5 years younger to C, then find the difference between the age of A and C?
         
       
      
      
      
          
      
      
          Answer & Explanation
         Answer: B) 9         
         
Explanation: Let the present ages of A & B to be ‘a’ & ‘b’ respectively. 
 Hence, 2 years ago, their ages must have been (a-2) & (b-2) respectively.
 Average of their ages at that time = 26 
 Hence,
 [(a-2)+(b-2)]/2 = 26
 (a-2)+(b-2) = 52
 a+b = 56
 Age of A, 5 year hence = 40 years 
 Hence, (a+5) = 40
 a = 35 years
 Hence, b = 56 - 35 = 21 years 
 B = (C-5)
 Hence, C = 21+5 = 26 years
 Age difference between A & C = 35 - 26 = 9 years.
       
      
      
      
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