6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Every year before the festive season,a shopkeeper increases the price of the product by 35% and then introduce two successive discount of 10% and 15% respectively.what is percentage loss and percentage gain ?

A) 3.27 % loss	B) 4.15 % loss
C) 3.27 % gain	D) 4.15 % gain

Answer & Explanation Answer: C) 3.27 % gain

Explanation:

Let cp= 100,
35 % increase in sp=135
10 % discount in 135((135*10)/100)=13.5
so 1st sp=(135-13.5)=121.5, again 15 % discount in 1st sp((121.5*15)/100)=18.225
2nd sp=(121.5-18.225)=103.275,

so finally cp=100,sp=103.275 ,gain by 3.27%

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

50 29156

Q:

The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?

A) 3.6	B) 4.6
C) 6.5	D) 7.3

Answer & Explanation Answer: B) 4.6

Explanation:

Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]

= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.

Required average = (9.2 / 2) = 4.6.

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Filed Under: Average

38 29127

Q:

The surface area of a cube is 1734 sq. cm. Find its volume

A) 2334 cubic.cm	B) 3356 cubic.cm
C) 4913 cubic.cm	D) 3478 cubic.cm

Answer & Explanation Answer: C) 4913 cubic.cm

Explanation:

Let the edge of the cube bea. Then,

6 $a^{2}$ = 1734

=> a = 17 cm.

Volume = $a^{3}$ = $17^{3}$ = 4193 cu.cm

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Filed Under: Volume and Surface Area

56 29118

Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

31 29118

Q:

3 pumps working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: D) 12

Explanation:

Let the required no of working hours per day be x.

More pumps , Less working hours per day (Indirect Proportion)

Less days, More working hours per day (Indirect Proportion)

$\begin{array}{r} \begin{matrix} P u m p s & 4 : 3 \end{matrix} \\ \begin{matrix} D a y s & 1 : 2 \end{matrix} \end{array}\} ⋮ ⋮ 8 : x$

=> (4 * 1 * x) = (3 * 2 * 8)

=> x=12

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Filed Under: Chain Rule

47 29084

Q:

What is the value of $\sqrt{1054 + \sqrt{196} + \sqrt{169} + \sqrt{64}}$ ?

A) 33	B) 37
C) 29	D) 31

Answer & Explanation Answer: A) 33

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 29013

Q:

Find: S.l. on Rs 6250 at 14% per annum for 146 days.

A) Rs.350	B) Rs.450
C) Rs.550	D) Rs.650

Answer & Explanation Answer: A) Rs.350

Explanation:

P = Rs. 6250, R = 14 % & T = (146/365) years = 2/5 years .

S.I= $R s . [\frac{6250 * 14 * \frac{2}{5}}{100}] = R s . 350$

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

66 28984

Q:

A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident

A) 30/100	B) 35/100
C) 45/100	D) 50/100

Answer & Explanation Answer: B) 35/100

Explanation:

Let A = Event that A speaks the truth

B = Event that B speaks the truth

Then P(A) = 75/100 = 3/4

P(B) = 80/100 = 4/5

P(A-lie) = $1 - \frac{3}{4}$ = 1/4

P(B-lie) = $1 - \frac{4}{5}$ = 1/5

Now, A and B contradict each other =[A lies and B true] or [B true and B lies]

= P(A).P(B-lie) + P(A-lie).P(B)

= $(\frac{3}{5} * \frac{1}{5}) + (\frac{1}{4} * \frac{4}{5}) = \frac{7}{20}$

= $(\frac{7}{20} * 100)$ = 35%

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Filed Under: Probability

64 28951

Quantitative Aptitude - Arithmetic Ability Questions

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