Quantitative Aptitude - Arithmetic Ability Questions

Q:

ΔXYZ is right angled at Y. If m∠Z = 30°, then find the value of (sinX - 3/√2).

 

A) (√6-6)/2√2 B) (√2-√3)/√6
C) -1/2 D) (1-2√3)/2
 
Answer & Explanation Answer: A) (√6-6)/2√2

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Q:

ΔDEF is right angled at E. If m∠F = 30 deg, then find the value of (cosD - 1/√2).

 

A) -1/2   B) (√6-1)/√3  
C) (√2-2)/2√2   D) √3-2
 
Answer & Explanation Answer: C) (√2-2)/2√2  

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Q:

∆DEF is right angled at E. If tanD = 12/5, then what is the value of secF ?

 

A) 5/12   B) 13/5  
C) 5/13 D) 13/12
 
Answer & Explanation Answer: D) 13/12

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Q:

If a2 + 1a2 = 3, then a3 + 1a3 = ?

 

A) 3√5 B) 2√5
C) 2√3 D) 3√3
 
Answer & Explanation Answer: B) 2√5

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Q:

Simplify : (27)-23

 

A) 1/18 B) 9
C) 1/9 D) 18
 
Answer & Explanation Answer: C) 1/9

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Q:

If p + 1p = 10, then the value of p4 + 1p4.

 

A) 52 B) 60
C) 62 D) 65
 
Answer & Explanation Answer: C) 62

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Q:

How much does a watch lose per day, if its hands coincide ever 64 minutes?

A) 32 8/11 B) 33 8/11
C) 34 8/11 D) 35 8/11
 
Answer & Explanation Answer: A) 32 8/11

Explanation:

55min spaces are covered in 60min

60 min. spaces are covered in (60/55 x 60) min= 65+5/11 min.

loss in 64min=(65+5/11)- 64 =16/11

Loss in 24 hrs (16/11 x 1/64 x 24 x 60) min= 32 8/11.

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Filed Under: Clocks
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Q:

"I am five times as old as you were, when I was as old as you are", said a man to his son. Find out their present ages, if the sum of their ages is 64 years ?

A) Father = 50; Son =14 B) Father = 40; Son =24
C) Father = 60; Son =4 D) Father = 48; Son =16
 
Answer & Explanation Answer: B) Father = 40; Son =24

Explanation:

Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.

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