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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?

A) 90 B) 89
C) 87.48 D) 86
 
Answer & Explanation Answer: A) 90

Explanation:

Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90.

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Filed Under: Profit and Loss

58 30148
Q:

The smallest number which when diminished by 7,  is divisible by  12, 16, 18, 21 and 28 is

A) 1008 B) 1015
C) 1022 D) 1032
 
Answer & Explanation Answer: B) 1015

Explanation:

Required Number = (L.C.M  of 12, 16, 18,21,28)+7

= 1008 + 7

= 1015

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Filed Under: HCF and LCM

101 30141
Q:

∆DEF is right angled at E. If secD = 17/8, then what is the value of cosF?

 

A) 15/17   B) 15/8  
C) 8/17   D) 17/15
 
Answer & Explanation Answer: A) 15/17  

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 30139
Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800 B) 43800
C) 83800 D) 73800
 
Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 30133
Q:

What is the value of (2 + tan600) ?

 

A)  3   B)  2/√3  
C)  4/√3   D)  2+√3
 
Answer & Explanation Answer: D)  2+√3

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 30120
Q:

What is the value of (1/√3 - sin45)?

 

A) 1/2√3   B) (√2-√3)/√6  
C) 1-√2   D) (4-√3)/2
 
Answer & Explanation Answer: B) (√2-√3)/√6  

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 30097
Q:

A Contractor employed a certain number of workers  to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the  scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?

A) 10 % B) 14 ( 2/7 )%
C) 20 % D) Can't be determined
 
Answer & Explanation Answer: B) 14 ( 2/7 )%

Explanation:

Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.

D * x +(100- D) * 2x= 175x 

=>  D= 25 days 

Now , the work done in 25 days = 25x 

Total work = 175x

Therefore, workdone before increasing the no of workers = 25x175x×100 % = 1427%

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Filed Under: Time and Work

107 30093
Q:

Find the Missing number in the given number series?

5, 9, 15, 23, ?, 45

A) 33 B) 29
C) 31 D) 35
 
Answer & Explanation Answer: A) 33

Explanation:

The given series follows a pattern that,

+4, +6, +8, +10, +12...

5

5 + 4 = 9

9 + 6 = 15

15 + 8 = 23

23 + 10 = 33

33 + 12 = 45

 

Hence, the missing number in the series is 33.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

3 30079