Quantitative Aptitude - Arithmetic Ability Questions

Q:

The number of trees in a town is 17640. If the numbers of trees increases annually at the rate of 5%, then how many trees were there 2 years ago?

A) 14000 B) 15000
C) 16000 D) 18000
 
Answer & Explanation Answer: C) 16000

Explanation:
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Filed Under: Percentage
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Q:

Select the related number from the given alternatives.
0.02 : 0.002 :: 1/3 : ?

A) 0.333 B) 1/30
C) 0.003 D) 3
 
Answer & Explanation Answer: B) 1/30

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Filed Under: Ratios and Proportions
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Q:

The sum of a fraction and 3 times its reciprocal is 19/4. What is the fraction?

A) 3/4 B) 4/3
C) 5/4 D) 4/5
 
Answer & Explanation Answer: A) 3/4

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Filed Under: Problems on Numbers
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Q:

What will come in the place of question mark (?) in the following question (You do not have to calculate the exact value)?

√(3099.985 ÷ 62.001 + 14.001) = ?

A) 8 B) 13
C) 18 D) 23
 
Answer & Explanation Answer: A) 8

Explanation:

Ans. 
√(3100 ÷ 62 + 14) = ?
√(50 + 14) = ?
√64 = ?
? = 8

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , GATE

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Q:

What is the value of (32 cos6x  48 cos4x + 18 cos2x  1)/[4 sin x cos x sin (60  x) cos (60  x) sin (60 + x) cos (60 + x)]?

A) 4 tan 6x B) 4 cot 6x
C) 8 cot 6x D) 8 tan 6x
 
Answer & Explanation Answer: C) 8 cot 6x

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Q:

An aeroplane flying horizontally at a height of 3 Km. above the ground is observed at a certain point on earth to subtend an angle of 60°. After 15 sec flight, its angle of elevation is changed to 30°. The speed of the aeroplane (taking √3 = 1.732) is

A) 230.63 m/sec B) 230.93 m/sec
C) 235.85 m/sec D) 236.25 m/sec
 
Answer & Explanation Answer: B) 230.93 m/sec

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Q:

Coefficient of x2 in (x + 9)(6 -­ 4x) is

A) 54 B) -4
C) ­30 D) 4
 
Answer & Explanation Answer: B) -4

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Q:

Both S.I. and C.I. is calculated with a similar rate of 10% per annum on a sum of rupees. If C.I. is calculated yearly for two years, then for what period must S.I. be evaluated such that S.I. = C.I.?

A) 4.2 years B) 2.1 years
C) 1.1 years D) 1.4 years
 
Answer & Explanation Answer: B) 2.1 years

Explanation:

Let time period of S.I. be T years.

Then for a principal amount, say P,

ATQ, as, S.I. = C.I. for rate =10%p.a. and

time for C.I. = 2(P x 10 x T)/100 = P{[ (100+10)/100 ]2-1}T/10 = [ 110/100 ]2–1 = [(11/10)2–1] = (121-100)/100T/10 = 21/100T = 21/10 = 2.1 years

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Filed Under: Simple Interest
Exam Prep: Bank Exams
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