Quantitative Aptitude - Arithmetic Ability Questions

Q:

In a trapezium ABCD, AB || CD, AB < CD, CD = 6 cm and distance between the parallel sides is 4 cm. If the area of ABCD is 16 sq.cm, then AB is

A) 1 cm B) 3 cm
C) 2 cm D) 8 cm
 
Answer & Explanation Answer: C) 2 cm

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Q:

Find the total surface area (in cm2) of a cube of side 7.5 cm.

A) 364.5 B) 446
C) 337.5 D) 684
 
Answer & Explanation Answer: C) 337.5

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Q:

Mr. Mike borrowed Rs. 8500 at 4% per annum C.I. The C.I. compounded annally for 2 years is :

A) Rs. 9139.6 B) Rs. 639.6
C) Rs. 9193.6 D) Rs. 693.6
 
Answer & Explanation Answer: D) Rs. 693.6

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Filed Under: Compound Interest
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Q:

A man walks 1 km on 1st day , 2 km on 2nd day , 3 km on 3rd day and so on . The total distance the man covers in 10 days is

A) 40 Km B) 50 Km
C) 55 Km D) 58 Km
 
Answer & Explanation Answer: C) 55 Km

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Filed Under: Time and Distance
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Q:

In the given figure, in triangle STU, ST = 8 cm,TU = 9 cm and SU = 12 cm. QU = 24 cm, SR = 32 cm and PT = 27 cm. What is the ratio of the area of triangle PQU and area of triangle PTR?

A) 1 : 1 B) 1 : 4
C) 2 : 3 D) Unknown
 
Answer & Explanation Answer: D) Unknown

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Filed Under: Volume and Surface Area
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Q:

The difference between compound interest compoundedevery 6 months and simple interest after 2 years is 248.10.The rate of interest is 10 percent. Find the sum

A) 12000 B) 14000
C) 16000 D) 18000
 
Answer & Explanation Answer: C) 16000

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Filed Under: Simple Interest

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Q:

What is the value of  4cos90-A sin390+A - 4sin90+A cos390-Acos180+8A2 ?

A) 1 B) -1
C) 0 D) 2
 
Answer & Explanation Answer: B) -1

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Filed Under: Simplification
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Q:

The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle?

A) 360sq metre B) 380 sq metre
C) 360 metre D) 400 sq metre
 
Answer & Explanation Answer: A) 360sq metre

Explanation:

Let the breadth of rectangle be x m.

Then, the length of rectangle = (x+ 6) m

Perimeter of rectangle = 2 (x+x+ 6) m

Therefore, 2 (x+x+ 6) = 84 m

4x+ 12 = 84

4x= 84 –12
4x = 72/4 = 18
Therefore, length of rectangle = 18 + 6 = 24 m = height of triangle

Diagonal of rectangle = √(324+576) = 30 m = base of triangle

Therefore, are of triangle =1/2× base × height =1/2× 24 × 30 = 360 sq. m

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