Quantitative Aptitude - Arithmetic Ability Questions

Q:

The average of 29 consecutive even integers is 60. The highest of these integers is

A) 88 B) 118
C) 176 D) 120
 
Answer & Explanation Answer: A) 88

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Filed Under: Numbers
Exam Prep: Bank Exams

1 1939
Q:

What is the value of sin225°+ sin265°?

A) 0 B) 1
C) 2 D) 4
 
Answer & Explanation Answer: B) 1

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Filed Under: Simplification
Exam Prep: Bank Exams

0 1938
Q:

Two trains move from stations M and N. Both trains move towards each other at speeds of 54 km/hr and 63 km/hr respectively. When they meeteach other, the second train has travel 100 km more than the first. What is the distance (in km) between M and N

A) 600 B) 700
C) 1300 D) 1500
 
Answer & Explanation Answer: C) 1300

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Filed Under: Problems on Trains

5 1938
Q:

A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at a speed of 4 km/hour and partly on bicycle at a speed of 9 km/hour . The distance travelled on foot is

A) 14 km B) 16 km
C) 20 km D) 18 km
 
Answer & Explanation Answer: B) 16 km

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Filed Under: Time and Distance
Exam Prep: Bank Exams

0 1938
Q:

What is the remainder when 6910 is divided by 81?

A) 25 B) 23
C) 21 D) 19
 
Answer & Explanation Answer: A) 25

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

1 1937
Q:

If x3  y3 = 81 and x – y = 3, then what is the value of x2 + y2?

A) 18 B) 21
C) 27 D) 36
 
Answer & Explanation Answer: B) 21

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Filed Under: Simplification
Exam Prep: Bank Exams

2 1937
Q:

P and Q are two alloys which are prepared by mixing tin and lead in the ratio of 12 : 5 and 4 : 3 respectively. If equal quantities of alloys are melted to form athird alloy R, then what is the ratio of tin and lead in alloy R?

A) 84 : 65 B) 57 : 35
C) 76 : 43 D) 78 : 47
 
Answer & Explanation Answer: C) 76 : 43

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Filed Under: Ratios and Proportions

2 1937
Q:

If p and q are the roots of the equation x2 –15x + r = 0 and p –q = 1, then what is the value of r ?

A) 55 B) 56
C) 60 D) 64
 
Answer & Explanation Answer: B) 56

Explanation:

In the below equation,

x2–15x + r = 0

sum of roots = p + q = -(-15)/1 = 15 (sum of roots for equation ax2+ bx + c is -b/a)

product of roots = pq = r/1 = r     (product of roots for equation ax2+ bx + c is c/a)

given p –q = 1

also we know that p+q = 15

subtracting the squares of both

(p+q)2 + (p-q)2 = 15^2–1

p2 + q2 + 2pq –p2 –q2 +2pq = 225 -1

4pq = 224

4r = 224

r = 56

 

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Filed Under: Simplification
Exam Prep: Bank Exams

0 1936