6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A and B start a business jointly. A invests Rs. 16,000 for 8 months and B remains in the business for 4 months, Out of total profit, B claims - of the profit. How much money was contributed by B ?

A) 12000	B) 12800
C) 13000	D) 14500

Answer & Explanation Answer: B) 12800

Explanation:

Let the total profit be Rs. x. Then, B = 2x/7 and A = (x - 2x /7) = 5x / 7.

So, A : B = 5x/7 : 2x/7 = 5 : 2.

Let B s capital be Rs. y. Then, (16000 * 8) / ( y * 4) = 5/2 <=> (16000 * 8 * 2) / (5 * 4) = 12800..

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Filed Under: Partnership

35 38187

Q:

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a

king of heart is:

A) 2/13	B) 1/13
C) 1/26	D) 1/52

Answer & Explanation Answer: C) 1/26

Explanation:

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) =n(E)/n(S)=2/52=1/26.

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Filed Under: Probability

7 38054

Q:

x and y are integers

x + y < 11 , and x > 6

What is the smallest possible value of x - y ?

A) 1	B) 24
C) 4	D) -2

Answer & Explanation Answer: C) 4

Explanation:

The smallest value will be obtained by giving x the smallest possible value while y gets the largest possible value. The smallest value for x = 7. This means that y will have to be less than or equal to 3 (so that x + y <11), but we want the largest value of y which is 3.

The difference, x - y will be 4.

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Filed Under: Problems on Numbers
Exam Prep: GRE

4 38052

Q:

A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?

A) 3	B) 5
C) 6	D) 9

Answer & Explanation Answer: B) 5

Explanation:

[(100 x 35) + (200 x 5)]men can finish the work in 1 day

Therefore, 4500 men can finish the work in 1 day. 100 men can finish it in 4500/100= 45 days.

This is 5 days behind Schedule

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Filed Under: Chain Rule

64 38034

Q:

Find out the wrong term in the following number series.

4, 16, 37, 58, 81.

A) 16	B) 37
C) 81	D) 4

Answer & Explanation Answer: C) 81

Explanation:

The series follows the following pattern.

4

16 = $4^{2}$

37 = $1^{2} + 6^{2}$

58 = $3^{2} + 7^{2}$

81 $\neq 5^{2} + 8^{2}$ .

Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

5 38017

Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer

Let the son's age be x years and the father's age be 4x years

$\Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline \therefore$ present age of the father = $\inline 4x$ = $\inline 4\times 8$ = 32 years

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Subject: Problems on Ages

204 38016

Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h	B) 15 km/h
C) 25 km/h	D) 20 km/h

Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be $f_{s}$ and that of slower horse be $s_{s}$ then

$f_{s} + s_{s} = \frac{50}{1} = 50$

and $\frac{50}{s_{s}} - \frac{50}{f_{s}} = \frac{5}{6}$

Now, you can go through options.

The speed of slower horse is 20km/h

Since, 20+30=50

and $\frac{50}{20} - \frac{50}{30} = \frac{5}{6}$

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Filed Under: Time and Distance

158 38013

Q:

If a * b = 2a - 3b + ab, then 3 * 5 + 5 * 3 is equal to :

A) 22	B) 23
C) 24	D) 25

Quantitative Aptitude - Arithmetic Ability Questions

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