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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Shivam Industries installed a flour mill for Rs. 300,000 five years ago. If the fixed annual rate of depreciation is 5% and they sold the mill for Rs. 250,000 their gain/loss % is?

 

 

A) No gain - No loss B) Loss 10%
C) Gain 12.5% D) Gain 10%
 
Answer & Explanation Answer: D) Gain 10%

Explanation:

Given that mill worth originally =3ooooo

Depreciation for 1 yr =300000x5/100= Rs. 15000

Then, depreciation for 5yrs = Rs. 75000

Value after 5yrs = 300000 - 75000 = Rs. 225000

Given Selling Price of the mill = Rs. 250000

Sp > CP

Gain = 250000 - 225000 = Rs. 25000

Gain% = 25000/250000 x 100 = 10%.

 

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

2 3047
Q:

If the mean of m observations out of n observations is n and the mean of remaining observations is m, then what is the mean of all n observations?

A) 2m –m^2/n B) 2m –m/n
C) 2m D) 2m –m
 
Answer & Explanation Answer: A) 2m –m^2/n

Explanation:

Mean of m observations is n

Mean of n-m observations is m

So total = nm+ (n-m)m

Total observations = n

Mean = Total / Total observations = (2mn-m^2)/n = 2m –m^2/n

 

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Filed Under: Simplification
Exam Prep: Bank Exams

0 3047
Q:

If the price of kerosene be raised by 11%, find by how much percent a house holder must reduce his consumption of kerosene so as not to increase his expenditure?

A) 11% B) 9.09%
C) 11.09% D) 8.25%
 
Answer & Explanation Answer: B) 9.09%

Explanation:

Let the price of kerosene be x and household
consumption be y.
Expenditure = xy
New cost of kerosene = 1.1x, let new household
consumption be z.
In order to not to increase expenditure,
xy = 1.1x * a
⇒ a= 10y/ 11
⇒ consumption should decrease by = 1/11 X 100 = 9.09%

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Filed Under: Percentage
Exam Prep: Bank Exams

2 3044
Q:

A student gets 22 marks more in French than what she got in German. Her German marks are 28% of the sum of her French and German marks. What are her French marks?

A) 14 B) 36
C) 18 D) 42
 
Answer & Explanation Answer: B) 36

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

7 3042
Q:

If a person repaid Rs. 22500 after 10 years of borrowing a loan, at 10% per annum simple interest find out what amount did he take as a loan?

A) 11,225 B) 11,250
C) 10,000 D) 7,500
 
Answer & Explanation Answer: B) 11,250

Explanation:

SI = PTR/100

SI = PX100/100

SI = P

So, Amount=P+SI=2P→22500 = 2P→P = 11250

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Filed Under: Simple Interest
Exam Prep: Bank Exams

4 3041
Q:

If a + b + c = 7/12, 3a – 4b + 5c = 3/4 and 7a – 11b – 13c = – 7/12, then what is the value of a + c?

A) 1/2 B) 5/12
C) 3/4 D) 1/4
 
Answer & Explanation Answer: B) 5/12

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

2 3037
Q:

What is the fourth proportional to 336, 288 and 161?

A) 184 B) 115
C) 138 D) 134
 
Answer & Explanation Answer: C) 138

Explanation:
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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

4 3034
Q:

The true discount on Rs.2562 due 4 months hence is Rs.122.The rate % is?

A) 12% B) 13 (1/3)%
C) 15% D) 14%
 
Answer & Explanation Answer: A) 12%

Explanation:

P.W = Rs.( 2562 - 122) = Rs.2440 

S.I on Rs.2440 for 4 months is Rs.122 

Rate = (100 x 122)/(2440 x [1/3]) % = 15%

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Filed Under: True Discount

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