6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A committee of 5 persons is to be formed from 6 men and 4 women. In how many ways can this be done when at least 2 women are included ?

A) 196	B) 186
C) 190	D) 200

Answer & Explanation Answer: B) 186

Explanation:

When at least 2 women are included.

The committee may consist of 3 women, 2 men : It can be done in $4 C_{3} * 6 C_{2}$ ways

or, 4 women, 1 man : It can be done in $4 C_{4} * 6 C_{1}$ ways

or, 2 women, 3 men : It can be done in $4 C_{2} * 6 C_{3}$ ways.

Total number of ways of forming the committees

= $4 C_{2} * 6 C_{3} + 4 C_{3} * 6 C_{2} + 4 C_{4} * 6 C_{1}$

= 6 x 20 + 4 x 15 + 1x 6

= 120 + 60 + 6 =186

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Filed Under: Permutations and Combinations

88 65777

Q:

Calculate the area (in cm2) of a circle whose diameter is 7 cm.

A) 38.5	B) 77
C) 32.5	D) 65

Answer & Explanation Answer: A) 38.5

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

0 65772

Q:

Relation Between Efficiency and Time

A is twice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B.In how many days they can complee the whole work; working together?

Answer

Ratio of times taken by A and B = 1 : 2.

The time difference is (2 - 1) 1 day while B take 2 days and A takes 1 day.

If difference of time is 1 day, B takes 2 days.

If difference of time is 30 days, B takes 2 x 30 = 60 days.

So, A takes 30 days to do the work.

A's 1 day's work = 1/30

B's 1 day's work = 1/60

(A + B)'s 1 day's work = 1/30 + 1/60 = 1/20

A and B together can do the work in 20 days.

Workspace

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Subject: Time and Work

255 65636

Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only	B) II and III only
C) I and III only	D) Either II or III only

Answer & Explanation Answer: D) Either II or III only

Explanation:

I. gives, S.I for 3 years = Rs. 4500.

II. gives, Rate = 10% p.a.

III. gives, (C.I.) - (S.I.) = Rs. 465.

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

Thus, II is redundant.

Also, from I and II, we get sum =

100 x 4500

= 15000.

10 x 3

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

Thus, III is redundant.

Either II or III is redundant.

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

0 65442

Q:

If $x^{2} + kx + k = 0$ , has two distinct real solutions, then the value of k will satisfy

A) k<0 or k>4	B) k>4 only
C) 0<k<4	D) k<0 only

Answer & Explanation Answer: A) k<0 or k>4

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 65428

Q:

Which of the following statement(s) is/are TRUE?

I . $\frac{1}{1 \times 3} + \frac{1}{3 \times 5} + \frac{1}{5 \times 7} + . . . + \frac{1}{11 \times 13} = \frac{12}{13}$

II. $\frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + . . . + \frac{1}{12 \times 13} = \frac{12}{13}$

A) Only I	B) Only II
C) Both I and II	D) Neither I nor II

Answer & Explanation Answer: B) Only II

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 65425

Q:

405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: A) 9

Explanation:

Let the total number of children be x.

Then, x * (20% of x) = 405

=> x * 20x/100 = 405

$\frac{1}{5} x^{2}$ = 405

=> x=45

Number of sweets received by each child = 20% of 45 = 9.

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Filed Under: Percentage

294 65422

Q:

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?

A) 100/11 min past 8	B) 120/11 min past 8
C) 90/11 min past 8	D) 80/11 min past 8

Answer & Explanation Answer: B) 120/11 min past 8

Explanation:

In this type of problems the formulae is $(5 x - 30) \times \frac{12}{11}$
x is replaced by the first interval of given time Here i.e 8
$(5 * 8 - 30) * \frac{12}{11}$
= $\frac{120}{11}$ min

Therefore the hands will be in the same straight line but not
together at $\frac{120}{11}$ min.past 8.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

102 65247

Quantitative Aptitude - Arithmetic Ability Questions

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