Quantitative Aptitude - Arithmetic Ability Questions

The given series is 15, 19, 27, 38, 55, 75

15

15 + 4 = 19

19 + 8 = 27

27 + 12 = 39

39 + 16 = 55

55 + 20 = 75

Hence, the odd number in the given series is 38.

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

Then, n(S) = Number ways of selecting 3 students out of 25

                = 25C3  = 2300.

         n(E)= 10C1*15C2 = 1050. 

P(E) = n(E)/n(s) = 1050/2300 = 21/46

Let man invested Rs. A And, after two years amount invested = (A +

 The formula to find the volume is given by just multiplying Length, Breadth and Height of that object. 

 Thus, V = L x B X H  

Volume Formulae :   

1. Volume of Cube of side 's' = s x s x s = s3  cubic units.   

2. Volume of Cylinder = πR2h cubic units.  

[Where R is Radius and h is height]

Cp1 = p2 - p1 ,
Cp2 = p3 - p2
..
..
..
Cp23 = p24 - p23
Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)
All terms get cancelled, except p1 = 2 and p24 = 89
So Sum = -p1 + p24
Sum of series = -2 + 89 = 87

Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.
Given SD makes 1/4 th of the total fleet.
=> 8 = 1/4 (21 + x)
=> 32 = 21 + x
=> x = 11
Therefore, the company has 11 small cars.

The numbers 0,1,2,3,4,5,6,7,8,9 are 10 in number while preparing telephone numbers any number can be used any number of times.

This can be done in 105ways, but '0' is there

So, the numbers starting with '0' are to be excluded is 94 numbers.

 Total 5 digit telephone numbers = 105- 94 = 3439

Here to convert 0.125 into %

First convert to fractio

Multiply and divide by 1000

=> 0.125 x 10001000 = 1251000 = 18

=> Now, $$\begin{gathered} in percentage \\ 18 x 100 = 12.5% \end{gathered}$$