6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A car runs at the speed of 50 kms per hour when not serviced and runs at 60 km./hr. when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?

A) 8.2 hrs	B) 6.5 hrs
C) 8 hrs	D) 7.2 hrs

Answer & Explanation Answer: D) 7.2 hrs

Explanation:

After servicing, the distance covered by car in 6 hours = 60 * 6 = 360 km Without servicing, speed of car = 50 kmph => Required time = Distance/speed = 360/50 = 7.2 hrs.

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Filed Under: Time and Distance

2 3847

Q:

Mr. Rajan invested Rs 1,00,000 in US Stock Markets when the GBPINR rate was 75. After one year his investment appreciated by 20% in GBP terms. He sold of his investments and repatriated the money to India at the then existing rate of 80. what was real returns in INR?

A) loss of 24%	B) gain of 28%
C) loss of 28%	D) gain of 20%

Answer & Explanation Answer: B) gain of 28%

Explanation:

Money invested by Rajan before 1 year was = Rs. 100000

Money in UK pounds @ 75 is = 100000/75 = 1333.33 Pounds

Now, after 1 year invested amount was appreciated by 20%

=> 20% of 1333.33 = 266.66

Total investment becomes = 1333.33 + 266.66 = 1600 Pounds

This 1600 Pounds @ Indian currency at 80 = 1600 x 80 = Rs. 1,28,000

Hence, Rajan's investment of Rs. 1,00,000 becomes Rs. 1,28,000 in 1 year

Therefore, his profit % = [(128000 - 100000)/100000] x 100 = 28%.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

9 3846

Q:

4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

A) 4	B) 8
C) 12	D) 16

Answer & Explanation Answer: D) 16

Explanation:

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$W a v e r s 4 : 8 D a y s 4 : 8$ :: 4:x

4 x 4 x x = 8 x 8 x 4

=> x= $\frac{8 * 8 * 4}{4 * 4}$

=> x = 16.

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Filed Under: Quantitative Aptitude - Arithmetic Ability

2 3842

Q:

What is the probability that a couple with four children have atleast one girl?

A) 0.0625	B) 0.9375
C) 0.5	D) 0.0257

Answer & Explanation Answer: B) 0.9375

Explanation:

Here,n = 4(children)

P(girl)= 0.5

P(of atleast one girl)= 1 - P(no girls)

= 1 - 0.0625 = 0.9375

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Filed Under: Probability

3 3838

Q:

$\sqrt{(\frac{(0.75)^{3}}{1 - 0.75} + [0.75 + {(0.75)}^{2} + 1])} = ?$

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: B) 2

Explanation:

$\sqrt{(\frac{(0.75)^{3}}{1 - 0.75} + [0.75 + (0.75)^{2} + 1])} = \sqrt{\frac{(0.75)^{3} + (1 - 0.75) [(1)^{2} + (0.75)^{2} + 1 \times 0.75]}{1 - 0.75}}$

= $\sqrt{\frac{(0.75)^{3} + [(1)^{3} - (0.75)^{3}]}{1 - 0.75}} = \sqrt{\frac{1}{0.25}} = \sqrt{4} = 2$

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Filed Under: Square Roots and Cube Roots

6 3836

Q:

Find the odd man out 1 4 9 16 22 36?

A) 9	B) 16
C) 22	D) 36

Answer & Explanation Answer: C) 22

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

Hence, the odd man in the series is 22.

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Filed Under: Odd Man Out
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13 3832

Q:

A man purchased a bullock and a cart for Rs 1800. He sold the bullock at a profit of 20% and the cart at a profit of 30%.His total profit was 155/6 %. Find the cost price of bullock.

A) Rs 650	B) Rs 750
C) Rs 900	D) Rs 800

Answer & Explanation Answer: B) Rs 750

Explanation:

CP of bullock and cart = 1800

Let price of bullock be x and cart be (1800 –x)

SP of bullock and cart = 1800 + 155/6 X 1800 = 2265

Also, 1.2x + 1.3 (1800 –x) = 2265

⇒1.2x –1.3x = -75

⇒x = 750

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

2 3830

Q:

Relation Between Efficiencies

6 boys and 8 girls finish a job in 6 days and 14 boys and 10 girls finish the same job in 4 days. In how many days working together 1 boy and 1 girl can finish the work?

Answer

Sol : In this kind of questions we find the work force required to complete the work in 1 day (or given unit of time) then we equate the work force to find the relationship between the efficiencies (or work rate) between the different workers.

Therefore, 6B+8G = 6 days

=> 6(6B+8G)= 1 day (inversely proportional)

=> 36B+48G =1 ( by unitary method)

Again 14B+10G = 4days

=> 56B+40G =1

so, here it is clear that either we employ 36B and 48G to finish the work in 1 day or 56B and 40G to finish the same job in 1 day. thus , we can say

=> 36B+48G = 56B+40G

=> G= 2.5B

Thus a Girl is 2.5 times as efficient as a boy.

Now, since 36B+48G = 1

=> 36B+48(2.5 B)=1

=>156B=1

i.e., to finish the job in 1 day 156 boys are required or the amount of work is 156 boys-days

Again 1G+1B=2.5B+1B=3.5B

Now, since 156 boys can finish the job in 1 day

so 1 boy can finish the job in 156 days

Therefore, 3.5 boys can finish the job in $\frac{1 \times 156}{3.5} = \frac{4}{7}$ days.

Quantitative Aptitude - Arithmetic Ability Questions

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