Quantitative Aptitude - Arithmetic Ability Questions

Q:

In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends?

A) 720 B) 360
C) 120 D) 24
 
Answer & Explanation Answer: D) 24

Explanation:

Given word is SCOOTY

ATQ,

Except S & Y number of letters are 4(C 2O's T)

Hence, required number of arrangements = 4!/2! x 2! = 4!

= 4 x 3 x 2

= 24 ways.

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Filed Under: Permutations and Combinations
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Q:

The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs. 110. Find the banker's discount and the banker's gain.

A) Rs.145 B) Rs.136
C) Rs.121 D) Rs.112
 
Answer & Explanation Answer: C) Rs.121

Explanation:

T.D. =Ö(P.W.*B.G)

B.G. =(T.D.)2/ P.W.      

       = Rs.[(110x110)/ 1100]

       = Rs. 11.

 

B.D.= (T.D. + B.G.) = Rs. (110 + 11) = Rs. 121.

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Filed Under: Banker's Discount

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Q:

A person walking 6/7 of his usual rate is 30 minutes late. What is his usual time ?

A) 2 hrs 50 min B) 3 hrs 25 min
C) 3 hrs D) 2 hrs 5 min
 
Answer & Explanation Answer: C) 3 hrs

Explanation:

Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 6/7.
Balance by the distance,
1 x t = (6/7)(t + 30)
7t = 6(t + 30)
we get t as,
t = 180 minutes = 3 hrs.

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Filed Under: Problems on Numbers
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Q:

A committee of 4 people is to be formed from a group of 9 people.How many possible committees can be formed?

A) 120 B) 162
C) 126 D) 170
 
Answer & Explanation Answer: C) 126

Explanation:

This question is a combination since order is not important.

 

Answer = 7C3 = 126

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Q:

In an examination, a student scores 4 marks for every correct answer and loses I mark for every wrong answer. If he attempts in all 60 questions and secures 130 marks, the number of questions he attempts correctly, is:

A) 35 B) 38
C) 40 D) 42
 
Answer & Explanation Answer: B) 38

Explanation:

Let the number of correct answers be X.

Number of incorrect answers = (60 – X).

Therefore, 4x – (60 – x) = 130 

=> 5x = 190  => x = 38

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Filed Under: Simplification

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Q:

Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had ?

A) 19 B) 23
C) 17 D) 15
 
Answer & Explanation Answer: B) 23

Explanation:

If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29
If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29
If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27
common number is only 23 so it will be answer

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Filed Under: Numbers
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Q:

If 3a=4b=6c and a+b+c=2729, then a2+b2+c2 =?

A) 81 B) 83
C) 87 D) None of these
 
Answer & Explanation Answer: C) 87

Explanation:

4b=6cb=32c    and   3a=4ba=43b=43(32c)=2c 

a+b+c=2729   2c+32c+c=2729  c=629

 

 a2+b2+c2=(a+b+b)2-2(ab+bc+ca) 

 

=(2729)2-22c×32c+32c×c+c×2c 

 

 =729×29-2×132 c2

= 87

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Q:

What is the profit or loss % when a shopkeeper bought 4 mangoes for Rs. 6 and sold them @ 4 mangoes for Rs. 4?

A) 36.333% B) 33.666%
C) 33.333% D) 36.666%
 
Answer & Explanation Answer: C) 33.333%

Explanation:

Cost of 4 mangoes = Rs. 6 

Cost of 1 mango = Rs. 6/4 = Rs. 1.5

Now, Selling Price of 4 mangoes = Rs. 4

Selling Price of 1 mango = Rs. 4/4 = Rs. 1.0

 

      • We observe that, S.P < C.P

 

Hence, the shopkeeper incurs a loss.

 

Required loss% = loss/C.P x 100

Loss = 1.5 - 1 = 0.5

C.P = 1.5

Loss% = (0.5/1.5) x 100

 = (5/15) x 100

 = 1/3 x 100

 = 100/3

 = 33.333%.

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Filed Under: Profit and Loss
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