6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In an election between two candidates 70% of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 7203 votes which was 60% of the total valid votes. Find the total number of voters enrolled in that election.

A) 18050	B) 17500
C) 17000	D) 7203

Answer & Explanation Answer: B) 17500

Explanation:

Let total number of votes enrolled = x
No. of voted cast = 70% of x = 0.7x
Valid votes = 98% of 0.7x
⇒ 60% of total valid votes = 7203 = 60% of 98% of 0.7x
⇒ 0.6 X 0.98 X 0.7x = 7203
⇒ x = 7203 / (0.6 X 0.98 X 0.7)
⇒ x = 17500

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Filed Under: Percentage
Exam Prep: Bank Exams

1 5254

Q:

Derivative of sinx by first principle?

A) -sinx	B) -cosx
C) cosx	D) sinx

Answer & Explanation Answer: C) cosx

Explanation:

Screenshot_(1)1519127168.png image

Thus, the derivative of sinx by first principle is cosx.

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Filed Under: Simplification
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4 5251

Q:

If $A = \frac{l o g_{3} (2187)}{5}$ and $B = l o g_{243} (2187)$ , then which one of the following is correct?

A) A	B) A=B
C) A>B	D) can't be determined

Answer & Explanation Answer: B) A=B

Explanation:

Given $A = \frac{\log_{3} (2187)}{5} a n d B = \log_{243} (2187)$

$B = \log_{3^{5}} (2187) = \frac{\log_{3} (2187)}{5}$

=> A

Therefore, A = B

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Filed Under: Logarithms
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7 5241

Q:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 1520 sq.m	B) 2420 sq.m
C) 2480 sq.m	D) 2520 sq.m

Answer & Explanation Answer: D) 2520 sq.m

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) sq.m

= 2520 sq.m

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Filed Under: Volume and Surface Area

1 5231

Q:

The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased ?

A) 90%	B) 88%
C) 85%	D) 84%

Answer & Explanation Answer: A) 90%

Explanation:

Let length, breadth and height of the room be 7, 3, 1 unit respectively.

Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit.

Now, length, breadth and height of room will become 3.5, 6 and 2 respectively.

Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit.

% Increase in the area of walls = (38-20)x100/20 = 90%.

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Filed Under: Area
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15 5231

Q:

Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?

A) 108	B) 107
C) 109	D) 110

Answer & Explanation Answer: C) 109

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109

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Filed Under: Ratios and Proportions
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15 5227

Q:

LCD of 12 and 18

A) 36	B) 42
C) 12	D) 6

Answer & Explanation Answer: A) 36

Explanation:

LCD is nothing but Lowest or Least Common Denominator

Here LCD of 12 and 18 means LCD of two fractions with denominators 12 and 18 respectively.

Therefore, LCM of 12 & 18 = 6 x 3 x 2 = 36

How to calculate LCD ::

The lowest common denominator or least common denominator (LCD) is the least common multiple (LCM) of the denominators of a set of fractions.

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Filed Under: HCF and LCM
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27 5223

Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

A) 6 yrs	B) 4 yrs
C) 8 yrs	D) 2 yrs

Answer & Explanation Answer: B) 4 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=> $\frac{5 p + 4}{6 p + 4} = \frac{6}{7}$

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

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Filed Under: Problems on Ages
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12 5217

Quantitative Aptitude - Arithmetic Ability Questions

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