Quantitative Aptitude - Arithmetic Ability Questions

If earlier he is getting Rs. 1  per hr and working for 1 hr, income = Rs. 1
Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs

Then income for 0.66667 hrs = Rs. 0.8889.

If payment per hr is increased by 33.33 %  and working hours dereased by 33.33%, then 11.11 % decrease in income.

From the given data,

                       Day      Capacity

A              ->    12          2

B              ->     8           3             2

A + B + C ->     2            12

=> Capacity of C = 12 - 5 = 7

Ratio of capacity of A : B : C = 2 : 3 : 7

Difference of wages of C & B = 4/5 x 1540

= 4 x 308 = Rs. 1232

Given numbers are 585 546 514 404 206 369
Then interchanging the 1st and 3rd digits of the given numbers, we get
585 645 415 404 602 963
Now, arranging them in ascending order
963 645 602 585 415 404
Then the last second number is 415.

PW = 100×Amount100+R×T

Let filling capacity of the pump be 'F' m3/min

Then, the filling capacity of the pump will be (F + 10) m3/min

From the given data,

$$\begin{gathered} 2400F - 2400F+10= 8 \\ ⇒ 2400 F+10-FF(F+10) =8 \\ ⇒ F2 + 10F - 3000 = 0 \\ ⇒ F = 50 m3/min \end{gathered}$$

CAPITAL = 7

Vowels = 3 (A, I, A)

Consonants = (C, P, T, L)

5 letters which can be arranged in  5P5=5!

Vowels A,I = 3!2!

No.of arrangements = 5! x 3!2!=360

0.46 = 46/100 = 23/50.

Sum of the numerator and denominator is 23 + 50 = 73

Let 'd' be the distance between A and B
K -time = d/10 + d/9 = 19d/90 hours
L -time = 2d/12 = d/6 hours
We know that, 10 min = 1/6 hours
Thus, time difference between K and L is given as 10 minutes.
=> 19d/90 - d/6 = 1/6
=> (19d-15d)/90 = 1/6
=> 4d/90 = 1/6
Thus,
d= 15/4 km = 3.75 km.

hence the distance between A and B is 3.75 km.