Quantitative Aptitude - Arithmetic Ability Questions

Q:

If log330 = 1a  and  log530=1b then the value of 3log302 is:

A) 3(1+a+b) B) 2(1-a-b)
C) 3(1-a-b) D) 3(1+a-b)
 
Answer & Explanation Answer: C) 3(1-a-b)

Explanation:
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Filed Under: Logarithms
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25 5679
Q:

What is the difference between the banker's discount and the true discount on Rs.8100 for 3 months at 5%

A) Rs. 2 B) Rs. 1.25
C) Rs. 2.25 D) Rs. 0.5
 
Answer & Explanation Answer: B) Rs. 1.25

Explanation:

F = Rs. 8100

R = 5%

T = 3 months = 1/4 years

 

BD=FTR100=8100×14×5100=Rs.101.25

 

TD=FTR100+TR=8100×14×5100+14×5=Rs.100

Therefore BD - TD = 101.25-100 = Rs.1.25

 

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Filed Under: Banker's Discount

1 5678
Q:

Find the area of the rectangle or square with the given dimensions s=10 feet

A) 500 B) 100
C) 200 D) 300
 
Answer & Explanation Answer: B) 100

Explanation:

A=S2

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Filed Under: Area
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Job Role: Bank PO

1 5675
Q:

Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ?

A) 5.75 kms B) 7.36 kms
C) 8.2 kms D) 6.98 kms
 
Answer & Explanation Answer: B) 7.36 kms

Explanation:

Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

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Filed Under: Time and Distance
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7 5673
Q:

The present of Rs.169 due in 2years at 4% per annum compound interest is

A) Rs.150.50 B) Rs.154.75
C) Rs.156.25 D) Rs.158
 
Answer & Explanation Answer: C) Rs.156.25

Explanation:

Present worth = 169/(1+4/100)^n = 156.25

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Filed Under: Simple Interest
Exam Prep: GRE
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4 5661
Q:

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

A) Rs. 456 B) Rs. 458
C) Rs. 558 D) Rs. 568
 
Answer & Explanation Answer: C) Rs. 558

Explanation:

Area to be plastered= [2(l + b) x h] + (l x b)

= [2(25 + 12) x 6] + (25 x 12)  

= (444 + 300)  

= 744 

 

Cost of plastering = Rs. 744 x (75/100)= Rs. 558

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1 5657
Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000 B) Rs.4500
C) Rs.7500 D) Rs.5000
 
Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
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9 5654
Q:

The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 

A) 7! x 7! B) 7! x 6!
C) 6! x 6! D) 7! x 5!
 
Answer & Explanation Answer: B) 7! x 6!

Explanation:

The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways.

 

 Required no.of ways is = 7P6.6! = 7!.6!

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Filed Under: Permutations and Combinations
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10 5650