Quantitative Aptitude - Arithmetic Ability Questions

SP of each car is Rs. 404415, he gains 15% on first car and losses 15% on second car.

The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on...
So,
22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.

Let the distance be 'd' kms.

According to the given data,

$$\begin{gathered} d30 - d50 = 4060 hrs \\ => 6d = 300 \\ => d = 50 kms. \\ \end{gathered}$$

Let original length = x and original breadth = y. 

Decrease in area = xy -[(80/100x) * (90/100y)]  

=[(xy-(18/25)xy)]

=(7/25)xy

Decrease % =[(7/25)xy * (1/xy) * 100] =28%

Required number of signals = 5P1 + 5P2 + 5P3 + 5P4 + 5P5

= 5 + 20 + 60 + 120 + 120 = 325

There are 7C2 ways of selecting two men, and 10C1 ways of selecting a woman.Since each position in the committee is different,arrange the three people in 3! ways.

So, 7C2*10C1*3! =1260

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$$\begin{gathered} ⇒A - 20A100 = 100000 \\ ⇒A = 1,25,000 \end{gathered}$$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = GainCPx 100 = 2500075000x100 = 1003= 33.33%

Money collected = (59.29 x 100) paise = 5929 paise.

  Number of members = 5929 = 77.