Quantitative Aptitude - Arithmetic Ability Questions

Simple Interest on Rs. (260-20) for a gven time= Rs.20 

Simple Interest on Rs. (260-20) for a half time  = Rs.10 

True Discount on Rs.250 = Rs.10  

True Discount on Rs.260 = Rs.[(10/250) x 260] = Rs. 10.40

Let Shilpa's present age is p years

According to question,

p = 4(x+4) – 4(x–4)

p = 4x+16 – 4x+16

p = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

Let the price of an item be 100After 25% decrease, price of item = 75Increase in price to get the original price = 100-75 = 25% increase to get the original price = 25/75 X 100 = 100/3 = 33.33%

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.

Average speed =  km/hr

                      =   km/hr

kl>k+1l+1 for (k,l) > 0 and  k > l 

Let     k = x+1    and   l = x

Therefore, x+1x>(x+1)+1(x)+1

 (x + 1) > x

Therefore, log(x+1)log(x)>log(x+2)log(x+1)

⇒logxx+1 >logx+1x+2

Let K = Kalyan's monthly salary
N = Nandu's monthly salary
S = Sarnesh's monthly salary.
Then from given data,
12% of K = 16% of N
S = N/2 => N = 2S
K = 16/12 x N = 16/12 x 2S
= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000