6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In how many different ways can five persons stand in a line for a group photograph?

A) 120	B) 240
C) 360	D) 720

Answer & Explanation Answer: A) 120

Explanation:

This is the number of permutations of five things taken all at a time.

Therefore, answer = $5 P_{5}$ = 120 ways

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Filed Under: Permutations and Combinations

2 6625

Q:

The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ?

A) Rs. 11828.80	B) Rs. 19828.80
C) Rs. 9828.80	D) Rs. 19328.80

Answer & Explanation Answer: B) Rs. 19828.80

Explanation:

Let the sum be Rs. P
P{ ${(1 + \frac{8}{100})}^{2}$ - 1 } = 2828.80

It is in the form of $a^{2} - b^{2} = (a + b) (a - b)$

P(8/100)(2 + 8/100) = 2828.80

P = 2828.80 / (0.08)(2.08)

= 1360/0.08 = 17000

Principal + Interest = Rs. 19828.80

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Filed Under: Compound Interest
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12 6622

Q:

Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ?

A) 18 years	B) 21 years
C) 23 years	D) 17 years

Answer & Explanation Answer: A) 18 years

Explanation:

At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x
12 years after:
Age of Sudeer = 4x+12
Age of Swetha = 3x+12
Now the equation is 3x+12=5/6(4x+12)
Solving equation we get x=6
Hence Swetha got married at the age of 18.

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Filed Under: Problems on Ages
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4 6620

Q:

When six fairs coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads ?

A) 15	B) 42
C) 16	D) 40

Answer & Explanation Answer: B) 42

Explanation:

The question requires you to find number of the outcomes in which at most 3 coins turn up as heads.

i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.

The number of outcomes in which 0 coins turn heads is $6 C_{0}$ =1

The number of outcomes in which 1 coin turns head is = $6 C_{1}$ =6

The number of outcomes in which 2 coins turn heads is $6 C_{2}$ =15

The number of outcomes in which 3 coins turn heads is $6 C_{3}$ =20

Therefore, total number of outcomes =1+6+15+20= 42 outcomes

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Filed Under: Permutations and Combinations

3 6619

Q:

The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is

A) 264	B) 284
C) 215	D) 302

Answer & Explanation Answer: A) 264

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22
13x/12 = x+22
x = 264

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Filed Under: Problems on Numbers
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4 6614

Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm	B) 50 gm
C) 55 gm	D) 60 gm

Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper = $\frac{80}{100} x 50$ = 40 g

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> $(50 + p) x \frac{90}{100}$ = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

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Filed Under: Alligation or Mixture
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20 6614

Q:

A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in ?

A) 8 hrs	B) 12 hrs
C) 6 hrs	D) 4 hrs

Answer & Explanation Answer: C) 6 hrs

Explanation:

Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.

Then, (1/x + 2/x + 3/x) = 1/2

=> 6/x = 1/2 => x = 12

So, B takes 6 hours to finish the work.

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Filed Under: Time and Work
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4 6613

Q:

One card is drawn from a pack of 52 cards , each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is neither a spade nor a king.

A) 0	B) 9/13
C) 1/2	D) 4/13

Answer & Explanation Answer: B) 9/13

Explanation:

There are 13 spades ( including one king). Besides there are 3 more kings in remaining 3 suits

Thus n(E) = 13 + 3 = 16

Hence $n (\bar{E}) = 52 - 16 = 36$

Therefore, $P (E) = \frac{36}{52} = \frac{9}{13}$

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Filed Under: Probability

6 6612

Quantitative Aptitude - Arithmetic Ability Questions

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