6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What would be the least number of years in which the simple interest on Rs.2600 at % will be an exact number of rupees ?

A) 2	B) 3
C) 4	D) 5

Answer & Explanation Answer: B) 3

Explanation:

$S . I = R s . [2600 * \frac{20}{3} * \frac{1}{100} * t]$

$S . I = R s . [\frac{520}{3} * t]$

t=3

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6 8006

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: A) 2years

Explanation:

Amount = Rs(30000 + 4347) = Rs.34347.

Let the time be n years. Then,

$30000 {[1 + \frac{7}{100}]}^{n} = 34347$

$\Leftrightarrow$ ${(\frac{107}{100})}^{n} = \frac{34347}{30000} = \frac{11449}{10000} = {(\frac{107}{100})}^{2}$

n= 2years.

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1 7997

Q:

19 friends went to a restaurant for a combined weekend dinner party. 13 of them spent Rs. 79 each on their dinner and the rest spent Rs. 4 more than the average expenditure of all the 19. What was the total money spent by them?

A) Rs. 1398.96	B) Rs. 1457.09
C) Rs. 1662.35	D) Rs. 1536.07

Answer & Explanation Answer: D) Rs. 1536.07

Explanation:

Let average expenditure was Rs. R

13 x 79 + 6x(R + 4) = 19R

=> R = Rs. 80.84

Total money = 19 x 80.84 = Rs. 1536.07.

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29 7994

Q:

Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?

A) 25 years	B) 24 years
C) 23 years	D) 22 years

Answer & Explanation Answer: C) 23 years

Explanation:

Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.

Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

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Filed Under: Problems on Ages
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11 7989

Q:

K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?

A) 12 pm	B) 1 pm
C) 11 am	D) 11:30 am

Answer & Explanation Answer: A) 12 pm

Explanation:

let 't' be the time after which they met since L starts.

Given K is 50% faster than L

50 t + 1.5*50(t-1) = 300

50 t +75 t = 300 + 75

t = 375 / 125 = 3 hrs past the time that L starts

So they meet at (9 + 3)hrs = 12:00 noon.

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Filed Under: Time and Distance
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4 7983

Q:

Find the perimeter of the rectangle or square with the given dimensions l = 5 feet, w = 2 feet?

A) 11ft	B) 13ft
C) 14ft	D) 15ft

Answer & Explanation Answer: C) 14ft

Explanation:

We know that,

Perimeter of rectangle = 2(L+W) = 2(5 + 2) = 2 (7) = 14 fts.

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Filed Under: Area
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1 7972

Q:

If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time?

A) Rs.51.25	B) Rs.52
C) Rs.53	D) Rs.54

Answer & Explanation Answer: A) Rs.51.25

Explanation:

Sum =Rs.(50 x 100/2x5)

= Rs. 500.

Amount

=[Rs.500x(1+5/100)²]

=Rs(500x21/20x21/20).

=Rs. 551.25

C.I

= Rs. (551.25 - 500)

= Rs. 51.25

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Filed Under: Compound Interest
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3 7965

Q:

Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train?

A) 105 mts	B) 115 mts
C) 120 mts	D) 140 mts

Answer & Explanation Answer: D) 140 mts

Explanation:

Speeds of two trains = 30 kmph and 58 kmph

=> Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s

Given a man takes time to cross length of faster train = 18 sec

Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.

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Filed Under: Time and Distance
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