Sawaal

 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Three graziers A,B and C rent a piece of pasture for a month. A puts in 27 cattle for 19 days, B 21 for 17 days and C 24 for 23 days. If at the end of the month the rent amount to Rs.237, how much ought to be paid by each.

Answer

A's cattle = 27 x 19 = 513


B's cattle = 21 x 17 = 357


C's cattle = 24 x 23 = 552


Ratio of cattle = 513 : 357 : 552


                    = 171 : 119 : 184


 


payment to be made by A = \inline 237\times \frac{171}{474}


                                     = Rs.85.50


payment to be made by B = \inline 237\times \frac{119}{474}


                                     = Rs.59.50


payment to be made by C = \inline 237\times \frac{184}{474}


                                     = Rs.92

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Subject: Partnership

7 8497
Q:

Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?

A) 1102 km B) 1060 km
C) 960 km D) 1250 km
 
Answer & Explanation Answer: C) 960 km

Explanation:

60(x + 1) = 64x

X = 15

60 x 16 = 960 km

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Filed Under: Time and Distance
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7 8487
Q:

The sum of the present ages of a father and his son is 126 years. 8 years ago their respective ages were in the ratio of 7 : 4. After 7 years what will be the ratio of ages of father and son?

 

A) 23 : 19 B)  17 : 11
C)  27 : 20 D) 34 : 23
 
Answer & Explanation Answer: B)  17 : 11

Explanation:
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Filed Under: Problems on Ages
Exam Prep: Bank Exams

35 8483
Q:

The average age of 7 boys is increased by 1 year when one of tem whose age is replaced by a girl. What is the age of the girl ?

A) 33 yrs B) 27 yrs
C) 21 yrs D) 29 yrs
 
Answer & Explanation Answer: D) 29 yrs

Explanation:

Let the avg age of 7 boys be 'p' years
Let the age of the girl be 'q' years
From given data,
The age of 7 boys = 7p years
Now the new average = (p + 1) when 22 yrs is replaced by q
Now the age of all 7 will become = 7(p + 1) yrs
Hence, 7p - 22 + q = 7(p + 1) yrs
7p - 22 + q = 7p + 7
q = 22 + 7 = 29

Therefore, the age of girl = q = 29 years.

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Filed Under: Average
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17 8482
Q:

Ajay who is a King, at his eleventh hour, called his three queens and distributed his gold in the following way: He gave 50% of his wealth to his first wife, 50% of the rest to his second wife and again 50% of the rest to his third wife. If their combined share is worth1,30,900 kilograms of gold, find the quantity of gold King Ajay was having initially?

A) 153145 kgs B) 147890 kgs
C) 152400 kgs D) 149600 kgs
 
Answer & Explanation Answer: D) 149600 kgs

Explanation:

Let the total quantity of gold be p kgs.

According to the question,

50% of p + 25% of p + 12.5% of p = 130900

87.5% of p = 130900

p = 130900 x 100/87.5  = 149600 kgs.

 

Therefore, the initial gold quantity that king has = p = 149600 kgs.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

7 8476
Q:

Lucky started working 2 years ago. Her starting salary was half of Karthik's salary at that time. Each year since then Lucky and Karthik have received a rise of 10% in their respective salary. What percentage (to the nearest percent) of Karthik's current salary is Lucky's current salary ?

A) 75% B) 22.5%
C) 35% D) 50%
 
Answer & Explanation Answer: D) 50%

Explanation:

Let the salary of Karthik 2 years ago be Rs.100
So, Lucky's salary 2 years ago was Rs.50

 

Karthik's present salary has seen two 10 percent increases. So as Lucky's salary.

So, Karthik's salary 1 year ago = 100 + 10% of 100 = 100 + 10 = 110.
Karthik's present salary = 110 + 10% of 110 = 110 + 11 = 121.

 

Lucky's salary 1 year ago = 50 + 10% of 50 = 50 + 5 = 55
Lucky's present salary = 55 + 10% of 55 = 55 + 5.5 = 60.5

 

Lucky's present salary of 60.5 = 50% of Karthik's present salary of 121.

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Filed Under: Percentage
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20 8450
Q:

Find the length of a train if it takes 10 seconds to cross a pole and double of this time to cross a platform of length 200 mts ?

A) 180 mts B) 190 mts
C) 200 mts D) 210 mts
 
Answer & Explanation Answer: C) 200 mts

Explanation:

Let the length of the train be 'L' mts

let the speed of the train be 'S' m/s

Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts

=> (L + 200)/S = 20

=> L/S + 200/S = 20

But from (1) L/S = 10

=> 200/S = 20 - 10

=> S = 20 m/s

Then, from (1)

=> L = 10 x 20 = 200 mts.

Hence, the length of the train = 200 mts.

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Filed Under: Problems on Trains
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12 8446
Q:

If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ?

A) 45 metric tonnes B) 47 metric tonnes
C) 55 metric tonnes D) 34 metric tonnes
 
Answer & Explanation Answer: A) 45 metric tonnes

Explanation:

2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton 

i.e. 3 engines of latter type consumes 1 ton for one hour

Hence 9 engines consumes 3 tons for one hour

For 15 hours it is 15 x 3 = 45 metric tonnes.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

3 8436