6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?

A) 2101 hrs	B) 4125 hrs
C) 5124 hrs	D) 6011 hrs

Answer & Explanation Answer: D) 6011 hrs

Explanation:

From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.

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Filed Under: Calendar
Exam Prep: Bank Exams , CAT , GATE , GRE
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27 7969

Q:

The probability that a card drawn at random from the pack of playing cards may be either a queen or an ace is:

A) 9/13	B) 11/13
C) 2/13	D) None of these

Answer & Explanation Answer: C) 2/13

Explanation:

Number of queen cards = 4

Number of ace cards = 4

P(either a queen or ace) = 4/52 + 4/52= 8/52 = 2/13

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Filed Under: Probability

3 7968

Q:

A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet?

A) 378	B) 472.5
C) 496	D) 630

Answer & Explanation Answer: A) 378

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

25 7968

Q:

Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes).

A) 18 min	B) 30 min
C) 27 min	D) 32 min

Answer & Explanation Answer: B) 30 min

Explanation:

Distance travelled by Ramu = 45 x 4 = 180 km

Somu travelled the same distance in 6 hours.

His speed = 180/6 = 30 km/hr

Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.

Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively.

Hence difference in the time taken = 0.5 hours = 30 minutes.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 7963

Q:

In a college, number of boys is 75% of number of girls. Difference between boys and girls is 35. On a particular day 20% boys were absent, then find the number of boys those who present?

A) 72	B) 84
C) 93	D) 81

Answer & Explanation Answer: B) 84

Explanation:

Ratio of girls and boys = 100% : 75% = 4:3

Difference is 1 unit = 35

So, 3 units = 35 x 3 = 105

If 20% absent, that’s mean 80% present.

So, present boys = 80% of 105 = $\frac{80 \times 105}{100} = 84$

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Filed Under: Percentage
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18 7960

Q:

A fraction becomes 2/3 when 1 is added to both, its numerator and denominator .And , it becomes 1/2 when 1 is subtracted from both the numerator and denominator. What is the fraction?

Answer

Let required fraction be $\frac{x}{y}$ then

$\frac{x+1}{y+1}=\frac{2}{3}\Rightarrow 3x-2y=-1$ ............. (i)

and $\frac{x-1}{y-1}=\frac{1}{2}\Rightarrow 2x-y=1$ ............ (ii)

Solving (i) and (ii) we get x=3, y=5

$\inline \therefore$ Required fraction = $\frac{3}{5}$

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Subject: Problems on Numbers

16 7958

Q:

Correct expression of 6.46 is

A) 640/99	B) 640/90
C) 64000/99	D) 640/9

Answer & Explanation Answer: A) 640/99

Explanation:

$6.46 = 6 + 0.46 = 6 + (\frac{46}{99}) \frac{(594 + 46)}{99} = > \frac{640}{99}$

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Filed Under: Decimal Fractions

13 7952

Q:

If the letters of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary, then the rank of the word VERMA is :

A) 108	B) 117
C) 810	D) 180

Answer & Explanation Answer: A) 108

Explanation:

The number of words beign with A is 4!

The number of words beign with E is 4!

The number of words beign with M is 4!

The number of words beign with R is 4!

Number of words beign with VA is 3!

Words beign with VE are VEAMR

VEARM

VEMAR

VEMRA

VERAM

VERMA

Therefore, The Rank of the word VERMA = 4 x 4! + 3! + 6 = 96 + 6 + 6 =108

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
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4 7935

Quantitative Aptitude - Arithmetic Ability Questions

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