6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is :

A) 260m	B) 280m
C) 360m	D) none of these

Answer & Explanation Answer:

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank Clerk

36 8301

Q:

A invested some money in 10% stock at 96. If B wants to invest in an equally good 12% stock, he must purchase a stock worth of :

A) Rs.80	B) Rs.115.20
C) Rs.120	D) Rs.125.40

Answer & Explanation Answer: B) Rs.115.20

Explanation:

For an income of Rs. 10, investment = Rs. 96.

For an income of Rs. 12, investment = Rs. (96/10)*12 = Rs. 115.20.

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Filed Under: Stocks and Shares

3 8295

Q:

A boat while travelling upstream covers a distance of 29 km at the speed of 6 km/h, whereas while travelling downstream it covers the same distance at a speed of 12 km/h. What is the speed of the boat in still water?

A) 6 kmph	B) 8 kmph
C) 9 kmph	D) 11 kmph

Answer & Explanation Answer: C) 9 kmph

Explanation:

Speed of boat in still water = 1/2 (12 + 6) = 9 kmph.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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10 8293

Q:

k, l, m together started a business. k invested Rs.6000 for 5 months l invested Rs.3600 for 6 months and m Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of l ?

A) Rs. 1640	B) Rs. 2500
C) Rs. 2160	D) Rs. 3000

Answer & Explanation Answer: C) Rs. 2160

Explanation:

=> 60x5 : 36x6 : 75x3

=> 100 : 72 : 75

=> 72/247 x 7410 = Rs. 2160

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Filed Under: Partnership
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5 8281

Q:

A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?

A) 1:3	B) 2:1
C) 3:2	D) 2:3

Answer & Explanation Answer: C) 3:2

Explanation:

Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7

We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7

Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9

Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.

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Filed Under: Ratios and Proportions
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14 8275

Q:

The True discount on Rs1760 due after a certain time at 12% per annum is Rs160. The time after which it is due is?

A) 15months	B) 5months
C) 12months	D) 10months

Answer & Explanation Answer: D) 10months

Explanation:

P.W = Rs. (1760 - 160) = Rs.1600

S.I on Rs.1600 at 12% is Rs. 160

Time = (100 x 160)/(1600 x 12) = 5/6 years = (5/6) x 12 months = 10 months

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Filed Under: True Discount

1 8269

Q:

${(31)}^{31} \times {(31)}^{- 27} = ?$

A) 961 x 861	B) 961 x 961
C) 961 x 2	D) 29791

Answer & Explanation Answer: B) 961 x 961

Explanation:

We know that $a^{m} \times a^{n} = a^{m + n}$

$∴ {(31)}^{31 - 27}$ = $31^{4}$ = 961 x 961.

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Filed Under: Numbers
Exam Prep: CAT
Job Role: Bank PO

11 8265

Q:

An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ?

A) 113/108	B) 105/103
C) 108/115	D) 103/113

Answer & Explanation Answer: B) 105/103

Explanation:

As given equal amounts of alloys are melted, let it be 1 kg.

Required ratio of gold and silver = $\frac{\frac{5}{13} + \frac{5}{8}}{\frac{8}{13} + \frac{3}{8}} = \frac{105}{103} .$

Hence, ratio of gold and silver in the resulting alloy = 105/103.

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Filed Under: Alligation or Mixture
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15 8255

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