6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ?

A) 61%	B) 75%
C) 55%	D) 81%

Answer & Explanation Answer: A) 61%

Explanation:

Let C.P.= Rs. 100.

Then, Profit = Rs.220,

S.P. = Rs.320.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs.320.

Profit = Rs. (320 - 125) = Rs. 195

Required percentage = $\frac{195}{320} \times 100$ == 60.9 =~ 61%

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Filed Under: Profit and Loss
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7 10449

Q:

When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ?

A) 22	B) 36
C) 32	D) 26

Answer & Explanation Answer: B) 36

Explanation:

Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
$\frac{54 x 30}{45}$ = 36.

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10 10430

Q:

How many days are there in k weeks k days ?

A) 8+k days	B) 7+1k days
C) 8k days	D) 7/k days

Answer & Explanation Answer: C) 8k days

Explanation:

As we know that a week has 7 days,

k weeks k days = (7k + k) days = 8k days.

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Filed Under: Calendar
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11 10429

Q:

On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?

A) Sunday	B) Monday
C) Tuesday	D) Wednesday

Answer & Explanation Answer: C) Tuesday

Explanation:

The year 1985 is an ordinary year. So, it has 1 odd day.

So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.

But, 19th June,1984 is Monday

S0, 19th June, 1985 is Tuesday.

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Filed Under: Calendar

25 10421

Q:

A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A) 29	B) 37
C) 42	D) 54

Answer & Explanation Answer: C) 42

Explanation:

After 10 days : 150 men had food for 35 days.

Suppose 125 men had food for x days.

Now, Less men, More days (Indirect Proportion)

$∴$ 125 : 150 :: 35 : x $\Leftrightarrow$ 125 x x = 150 x 35

$\Rightarrow x = \frac{150 \times 35}{125} = 42$

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16 10421

Q:

The letters of the word CASTIGATION is arranged in different ways randomly. What is the chance that vowels occupy the even places ?

A) 0.04	B) 0.043
C) 0.047	D) 0.05

Answer & Explanation Answer: B) 0.043

Explanation:

Vowels are A I A I O,

C A S T I G A T I O N

(O) (E) (O) (E) (O) (E) (O) (E) (O) (E) (O)

So there are 5 even places in which five vowels can be arranged and in rest of 6 places 6 constants can be arranged as follows :

$n (E) = \frac{5 P_{5}}{2! * 2! (A, I a r e 2 t i m e s)} * \frac{6 P_{6}}{2! (T i s 2 t i m e s)} = 21600$

$n (S) = \frac{11!}{2! * 2! * 2! (A, I a r e 2 t i m e s)} = 4989600$

$\frac{21600}{4989600} = 0.043$

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Filed Under: Probability
Exam Prep: GRE

7 10421

Q:

R enter into a partnership in the ratio 2 : 3 : 5 . After 2 months, P increases his share 20% and Q by 10%. If the total profit at the end of one year is Rs 1,90,500, what amount will 'R' receive at the end of year as share in profit ?

A) Rs. 90500	B) Rs. 87500
C) Rs. 88900	D) Rs. 90000

Answer & Explanation Answer: D) Rs. 90000

Explanation:

Ratio of investments for 1 year

=> (P : Q : R) = (2x2 + 2.4x10) : (3x2 + 3.3x10) : (5x12)

=> (P : Q : R) = 28 : 39 : 60

Now R share = 190500 x 60/127 = Rs. 90000.

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10 10415

Q:

An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item?

A) Rs. 90	B) Rs. 75
C) Rs. 55	D) Rs. 40

Answer & Explanation Answer: D) Rs. 40

Explanation:

Let the cost price of the item = Rs. 50

Sold at 10% loss => for Rs. 50 loss S.P = Rs. 45

From the given data,

25/2 % gain if it is sold at Rs. 9 more

56.25 - 45 = 9

=> 11.25 = 9

=> 22.5 = 18

=> 45 = 36

=> 50 = ?

=> $C . P = \frac{50 x 36}{45} = 40$

Hence, the Cost price of the item = Rs. 40.

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15 10410

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