6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

A) 1 : 10	B) 10 : 1
C) 9 : 11	D) 11 : 9

Answer & Explanation Answer: A) 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk :: Water

6.4 0

$\frac{8}{1 + \frac{3}{8}} = \frac{64}{11}$

$\frac{64}{11}$ $\frac{64}{10} - \frac{64}{11}$

=> Milk : Water = 110 : 11 = 10 : 1

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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29 9551

Q:

A salesman calculated his profit on the marked price and finds it to be 30%. He forgets the fact that he gave a discount of 20%. What is his actual profit percentage?

A) 260/11%	B) 18.4%
C) 22.5%	D) 100/7%

Answer & Explanation Answer: D) 100/7%

Explanation:

When profit is calculated on Marked Price (M.P) then,

C.P = M.P - P%

Let M.P = 100

=> C.P = 100 - 30 = 70

But S.P = Rs. 80 as he gave 20% discount,

Now, Actual Profit = $\frac{80 - 70}{70} x 100$

= 100/7 %

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Filed Under: Profit and Loss
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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18 9533

Q:

8 years ago Rama's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter . Find the present age of Rama?

Answer

Let Rama's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow 2(x+16)= 5x+16$

$2x+32=5x+16$

$3x=16$

$x=\frac{16}{3}$ years

Hence, present age of Rama = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

28 9529

Q:

A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing?

A) 64000 liters	B) 56000 liters
C) 78000 liters	D) 60000 liters

Answer & Explanation Answer: B) 56000 liters

Explanation:

Let x liter be the per day filling and v litr be the capacity of the reservoir, then

90x + v = 40000 * 90 -----(1)

60x + v= 32000 * 60 ------(2)

solving eq.(1) and (2) , we get

x = 56000

Hence , 56000 liters per day can be used without the failure of supply.

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Filed Under: Time and Work

8 9522

Q:

R enter into a partnership in the ratio 2 : 3 : 5 . After 2 months, P increases his share 20% and Q by 10%. If the total profit at the end of one year is Rs 1,90,500, what amount will 'R' receive at the end of year as share in profit ?

A) Rs. 90500	B) Rs. 87500
C) Rs. 88900	D) Rs. 90000

Answer & Explanation Answer: D) Rs. 90000

Explanation:

Ratio of investments for 1 year

=> (P : Q : R) = (2x2 + 2.4x10) : (3x2 + 3.3x10) : (5x12)

=> (P : Q : R) = 28 : 39 : 60

Now R share = 190500 x 60/127 = Rs. 90000.

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Filed Under: Partnership
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10 9520

Q:

The marked price of an article is increased by 25% and the selling price is increased by 16.66%, then the amount of profit doubles. If the original marked price be Rs. 400 which is greater than the corresponding cost price by 33.33%, what is the increased selling price?

A) Rs. 380	B) Rs. 420
C) Rs. 460	D) Rs. 440

Answer & Explanation Answer: B) Rs. 420

Explanation:

As given in the question, Marked price is 25% more than the Cost price.

=> C.P of the article = $\frac{3}{4} x 400 = 300$

Now,

Let the original S.P of the article be Rs. P

Now the new S.P = P + $\frac{(16.666 + 13.333)}{300} x P$

=> S.P = $\frac{7 P}{6}$

According to the question,

$\frac{7 P}{6} - 300 = 2 (P - 300)$

=> 5P = 1800

=> P = Rs. 360

Hence, the increased S.P = 360 x 7/6 = Rs. 420.

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Filed Under: Profit and Loss
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11 9508

Q:

On 1st Jan, 2005 Saturday falls. What day of the week was it on 1st Jan, 2006?

A) Saturday	B) Monday
C) Sunday	D) Tuesday

Answer & Explanation Answer: C) Sunday

Explanation:

The year 1985 is an ordinary year. So, it has 1 odd day.

So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.

But, 19th June,1984 is Monday

S0, 19th June, 1985 is Tuesday.

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Filed Under: Calendar

17 9503

Q:

Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $324 per week. How much does she earn in dollars per hour?

A) 11	B) 10
C) 9	D) 8

Quantitative Aptitude - Arithmetic Ability Questions

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