6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum?

A) 2.9 years	B) 3.5 years
C) 4.2 years	D) 4.7 years

Answer & Explanation Answer: B) 3.5 years

Explanation:

Given that Rs. 1860 will become Rs. 2641.20 at 12%

=> Simple Interest = 2641.20 - 1860 = Rs. 781.20

We know I = PTR/100

=> 781.20 x 100 = 1860 x T x 12

=> T = 78120/1860x12

=> T = 78120/22320

=> T = 3.5 years.

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Filed Under: Simple Interest
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30 12272

Q:

How many $\frac{1}{8}$ ' s are there in $37 \frac{1}{2}$ ?

A) 300	B) 400
C) 500	D) 600

Answer & Explanation Answer: A) 300

Explanation:

$37 \frac{1}{2} = \frac{75}{2}$

Required number = $\frac{\frac{75}{2}}{\frac{1}{8}}$ = 75 x 4 = 300

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Filed Under: Simplification
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23 12259

Q:

Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ?

A) 11 & 17	B) 7 & 17
C) 9 & 21	D) 13 & 23

Answer & Explanation Answer: C) 9 & 21

Explanation:

Let the two numbers be x and y

Given x : y = 3 : 7 .....(1)

Now, x+6 : y+6 = 5 : 9 .....(2)

From (1), x = 3y/7

From (2), 5y - 9x = 24

=> 5y - 9(3y/7) = 24

=> y = 21

=> From(1), x = 9

Hence, the two numbers be 9 and 21

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Filed Under: Ratios and Proportions
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36 12254

Q:

Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ?

A) 70 years	B) 30 years
C) 60 years	D) 40 years

Answer & Explanation Answer: B) 30 years

Explanation:

Let Karan’s present age be x years and Shiva’s present age be y years.
Then, according to the first condition,
x - 10 = 3(y - 10) or x - 3y = - 20 ..(1)
Now, Karan’s age after 10 years = (x + 10) years
Shiva’s age after 10 years = (y + 10)
(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2)
Solving (1) and (2), we get x = 70 and y = 30
Karan’s age = 70 years and Shiva’s age = 30 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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12 12223

Q:

A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:

A) 25%	B) 21.14%
C) 22.54%	D) 27.32%

Answer & Explanation Answer: C) 22.54%

Explanation:

C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224.

S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500.

Profit = 1500 - 1224 = Rs.276

Profit % = $\frac{P r o f i t}{C . P} \times 100$ = $\frac{276}{1224} \times 100$ = 22.54%.

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Filed Under: Profit and Loss
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8 12214

Q:

How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?

A) 1000	B) 100
C) 500	D) 999

Answer & Explanation Answer: B) 100

Explanation:

1 million distinct 3 digit initials are needed.

Let the number of required alphabets in the language be ‘n’.

Therefore, using ‘n’ alphabets we can form n * n * n = $n^{3}$ distinct 3 digit initials.

Note distinct initials is different from initials where the digits are different.

For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.

This $n^{3}$ different initials = 1 million

i.e. $n^{3} = 10^{6}$ (1 million = $10^{6}$ )

=> n = $10^{2}$ = 100

Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.

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Filed Under: Permutations and Combinations

7 12211

Q:

Rs. 700 is divided among A, B, C so that A receives half as much as B and B half as much as C. Then C's share is

A) Rs 200	B) Rs 300
C) Rs 400	D) Rs 500

Answer & Explanation Answer: C) Rs 400

Explanation:

Let C = x.
Then B = x/2
and A = x/4

A:B:C = 1:2:4.
C's share Rs.[(4/7)*700) = 400

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Filed Under: Partnership

14 12209

Q:

A contractor undertook a project to complete it in 20 days which needed 5 workers to work continuously for all the days estimated. But before the start of the work the client wanted to complete it earlier than the scheduled time, so the contractor calculated that he needed to increase 5 additional men every 2 days to complete the work in the time the client wanted it:

If the work was further increased by 50% but the contractor continues to increase the 5 workers o every 2 days then how many more days are required over the initial time specified by the client.

A) 1 day	B) 2 days
C) 5 days	D) None of these

Answer & Explanation Answer: B) 2 days

Explanation:

Total work = 100+50 = 150man-days

In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.

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Filed Under: Time and Work

15 12203

Quantitative Aptitude - Arithmetic Ability Questions

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