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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

∆DEF is right angled at E. If m∠F = 45°, then find the value of (tanD - √3/2).

 

A) -√3/2 B) -1/2√3
C) (2-√3)/2 D) (3√3-1)/3
 
Answer & Explanation Answer: C) (2-√3)/2

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 15986
Q:

Choose the figure which is different from the rest three.

 

 

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: D) 4

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 15975
Q:

Read the following information and answer the questions given below:

A has 28 elements, B has 32 elements and A U B has 40 elements.

How many elements does A ∩ B have?

A) 12 B) 8
C) 10 D) 20
 
Answer & Explanation Answer: D) 20

Explanation:
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Filed Under: Quantitative Aptitude - Arithmetic Ability

0 15954
Q:

What value should come in place of the question mark (?) in the following question?

264÷576+112+12 = ?2

A) 44 B) 12
C) 15 D) 14
 
Answer & Explanation Answer: B) 12

Explanation:
264 / 24 + 121 + 12 = (?)^2 11 + 121 + 12 = (?)^2 144 = (?)^2 (?) = 12
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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 15951
Q:

A triangle has a perimeter 13. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?

A) 4 B) 6
C) 8 D) None of the above
 
Answer & Explanation Answer: B) 6

Explanation:

The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers. 

 

    • Option A  cannot be correct because 4 would not be the longest side.(sides 4, 5, and 4)   

 

    • Option B could be correct because the other two sides would be 3 and 4.  

 

    • Option C cannot be correct because this third side would be greater than the sum of the other two sides.

 

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Filed Under: Area
Exam Prep: GRE

6 15933
Q:

The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop? 

A) 444 B) 344
C) 244 D) 144
 
Answer & Explanation Answer: D) 144

Explanation:

Given ratio of pens and pencils = 3 :2

Number of Pens = 3x

Number of Pencils = 2x

Average number of pencils & Pens = 3x + 2x2 = 180

5x = 360

=> x = 72


Hence, the number of pencils = 2x = 72 x 2 = 144.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

36 15897
Q:

Find the appropriate relation for quantity1 and quantity2 in the following question:

Quantity 1: In an examination, Ankita scored 35 marks less than Puneeta. Puneeta scored 65 more marks than Meenakshi. Rakhi scored 115 marks, which is 20 marks more than Meenakshi's. Simpy scored 108 marks less than the maximum marks of the test. What approximate percentage of marks did Simpy score in the examination, if she got 67 marks more than Ankita?

Quantity 2: The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area?

A) Quantity1 < Quantity2 B) Quantity1 ≤ Quantity2
C) Quantity1 ≥ Quantity2 D) Quantity1 > Quantity2
 
Answer & Explanation Answer: D) Quantity1 > Quantity2

Explanation:

Quantity1-
Rakhi’s marks= 115
Meenakshi’s marks= 115 - 20 = 95
Puneeta’s marks= 95 + 65= 160
Ankita’s marks=160 - 35= 125
Simpy’s marks= 125+ 67= 192
Total maximum marks= 192 + 108= 300
Required percentage marks of Simpy
= 192300×100=64%
Quantity2-
Let length and breadth be 100.

After increase in length it become 160, then
reduction in breadth be ‘x’
Now, 160*x= 100*100
Hence, x = 10000160=62.5

100-62.5=37.5%

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

2 15896
Q:

How many arrangements can be made out of the letters of the word DRAUGHT, the vowels never beings separated?

A) 1440 B) 720
C) 360 D) 640
 
Answer & Explanation Answer: A) 1440

Explanation:

There are 7 letters in the word DRAUGHT, the two vowels are A and U. Since, the vowels are not to be separated, AU can be considered as one entity. Therefore, the number of letters will be 6 instead of 7. The permutations will be P(6,6) = 6! ways.

 

But the two vowels A and U can be arranged in two ways, i.e. AU and UA. The required number of arrangements = 2!.6! = 1440 ways.

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Filed Under: Permutations and Combinations

15 15896