6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is :

A) 12	B) 137
C) 14	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let the three integers be x, x + 2 and x + 4. Then, 3x = 2 (x + 4) + 3 <=> x = 11.

Third integer = x + 4 = 15.

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Filed Under: Problems on Numbers

38 19104

Q:

3 x 0.3 x 0.03 x 0.003 x 30 =?

A) 0.0000243	B) 0.000243
C) 0.00243	D) 0.0243

Answer & Explanation Answer: C) 0.00243

Explanation:

3 x 3 x 3 x 3 x 30 = 2430. Sum of decimal places = 6

Therefore, 3 x 0.3 x 0.03 x 0.003 x 30 = 0.002430 = 0.00243

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Filed Under: Decimal Fractions

72 19095

Q:

A boatman can row 3 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current ?

A) 1/3 kmph	B) 2/3 kmph
C) 1/4 kmph	D) 1/2 kmph

Answer & Explanation Answer: D) 1/2 kmph

Explanation:

Speed in upstream = Distance / Time = 3 x 60/20 = 9 km/hr.

Speed in downstream = 3 x 60/18 = 10 km/hr

Rate of current = (10-9)/2 = 1/2 km/hr.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

32 19026

Q:

If Rs.10 be allowed as true discount on a bill of Rs.110 at the end of a certain time , then the discount allowed on the same sum due at the end of double the time is

A) 18.20	B) 18.33
C) 18	D) 18.30

Answer & Explanation Answer: B) 18.33

Explanation:

Present worth = Amount - True Discount = 110 -10 = Rs.100

SI on Rs.100 for a certain time = Rs.10

SI on Rs.100 for doube the time = Rs.20

True Discount on Rs.120 = 120 - 100 = Rs.20

True Discount on Rs.110 = $(110 \times \frac{20}{120})$ = Rs.18.33

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Filed Under: True Discount

6 19007

Q:

Which of the following number is largest among all?

0.7,0.77,0.077, 0.070707

A) 0.070707	B) 0.077
C) 0.77	D) 0.7

Answer & Explanation Answer: C) 0.77

Explanation:

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

0 18994

Q:

The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)

A) 19 years	B) 16 years
C) 18 years	D) 20 years

Answer & Explanation Answer: D) 20 years

Explanation:

Present total age of the members = 26(5) = 130 years.

Present age of the youngest member = 10 years

Present total age of the remaining four members = 130 -10 = 120 years

Their average age at the time of the birth of the youngest member = $\frac{[120 - (4 \times 10)]}{4}$ = 30 - 10 = 20 years.

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Filed Under: Problems on Ages
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

19 18976

Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2	B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2	D) Quantity 1 ≤ Quantity 2

Answer & Explanation Answer: A) Quantity 1 > Quantity 2

Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ $\frac{1}{x - 9}$

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = $\frac{1}{15} + \frac{1}{10} + \frac{1}{6}$
⇒ Net part filled in 1 hour = $\frac{4 + 6 + 10}{60}$
⇒Net part filled in 1 hour = $\frac{20}{60} = \frac{1}{3}$
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

2 18928

Q:

Three friends, P, Q and R started a partnership business investing money in the ratio of 5 : 4 : 2 respectively for a period of 3 years. What is the amount received by P as his share in the total profit ?

a. Total amount invested in the business in Rs. 22,000.

b. Profit earned at the end of 3 years is 3/8 of the total investment.

c. The average amount of profit earned per year is Rs. 2750.

A) Only c is sufficient	B) Both a & b are sufficient
C) Both A & B gives result	D) None

Answer & Explanation Answer: C) Both A & B gives result

Explanation:

a and b give, profit after 3 years = Rs.(3/8 x 22000) = Rs.8250.

From c also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250.

∴ P's share = Rs.(8250 x 5/11) = Rs. 3750.

Thus, (either C is redundant) or (a and b are redundant).

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 18900

Quantitative Aptitude - Arithmetic Ability Questions

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