Quantitative Aptitude - Arithmetic Ability Questions

Let l = 9 ft.

Then l + 2b = 37

=> 2b = 37 – l = 37 – 9 = 28

b = 28/2 = 14 ft.

Area = lb = 9 × 14 = 126 sq. ft.

Let the required no of binders be X.

Less books , Less binders       (Direct Proportion)

More days, Less binders         (Indirect proportion)

 Books900:660Days12 : 10⋮⋮ 18:x

Therefore, (900 * 12 * x) =  (660 * 10 * 18)  

=> x = 11

We already know that the calendar after a leap year repeats again after 28 years.

Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.

Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,

part filled by tap X in 1 minute = 1/30

part filled by tap Y in 1 minute = 1/40

Tap Z can empty the tank in 60 minutes. Therefore,

part emptied by tap Z in 1 minute = 1/60

Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24

i.e., the tank can be filled in 24 minutes.

Let the number be 'x'

Then, according to the given data,

 52x-25x52xx100

= 2125x100

= 84%

L.C.M. of 5, 6, 7, 8 = 840.

 Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

 Required number = (840 x 2 + 3) = 1683.

Area of the room=(544 * 374)

size of largest square tile= H.C.F of 544 & 374 = 34 cm

Area of 1 tile = (34  x  34) cm2

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

Let x128=162x

Then, $$\begin{gathered} x2=128×162 =64×2×18×9 \\ =82×62×32 = 8×6×3 =144 \end{gathered}$$

∴x=12