6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In measuring the sides of a rectangle, one side is taken 5% in excess and the other 4% in deficit. Find the error percent in the area, calculate from the those measurements.

A) .7%	B) 0.8%
C) 0.9%	D) 0.3%

Answer & Explanation Answer: B) 0.8%

Explanation:

let x and y be the sides of the rectangle then

correct area = $\frac{105}{100} x \times \frac{96}{100} y$

Error% = $\frac{504}{500} x y - x y = \frac{4}{500} x y$ %

$\frac{4}{500} x y \times \frac{1}{x y} \times 100 = \frac{4}{5} = 0.8$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

11 19050

Q:

Pencils, Pens and Exercise books in a shop are in the ratio of 10: 2 : 3. If there are 120 pencils, the number of exercise books in the shop is:

A) 26	B) 36
C) 46	D) 56

Answer & Explanation Answer: B) 36

Explanation:

Let Pencils = 10x, Pens = 2x & Exercise books = 3x. Now, 10x = 120 hence x = 12.
Number of exercise books = 3x = 36.

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Filed Under: Ratios and Proportions

44 19041

Q:

What is the value of (2 - tan60°) ?

A) -1/√3	B) (√3-4)/2√3
C) -1/2	D) 2-√3

Answer & Explanation Answer: D) 2-√3

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

1 18982

Q:

Consider the following frequency distribution:

x f

8 6

5 4

6 5

10 8

9 9

4 6

7 4

What is the median for the distribution?

A) 6	B) 7
C) 8	D) 9

Answer & Explanation Answer: C) 8

Explanation:

Summation of frequencies = 6+4+5+8+9+6+4 = 42

Median = mid value = average of 21st and 22nd value

Arranging data in increasing order we get

x f

4 6

5 4

6 5

7 4

8 6

9 9

10 8

So mid value i.e 21st and 22nd value = 8

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Filed Under: Average
Exam Prep: Bank Exams

0 18939

Q:

Classify the triangle as a type of triangle if the sides of the triangle are 6, 12 and 13 units.

A) Right angled triangle	B) Obtuse angled triangle
C) Acute angled triangle	D) None of these

Answer & Explanation Answer: C) Acute angled triangle

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

0 18936

Q:

A tailor has 37.5 metres of cloth and he has to make 8 pieces out of a metre of cloth. How many pieces can he make out this cloth ?

A) 300	B) 360
C) 400	D) 450

Answer & Explanation Answer: A) 300

Explanation:

Length of each piece = (1/8) m = 0.125 m

Required no of pieces = (37.5/0.125) = (375 * 100) / 125 = 300.

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Filed Under: Decimal Fractions

36 18902

Q:

The probability of success of three students X, Y and Z in the one examination are 1/5, 1/4 and 1/3 respectively. Find the probability of success of at least two.

A) 1/4	B) 1/2
C) 1/6	D) 1/3

Answer & Explanation Answer: C) 1/6

Explanation:

P(X) = $\frac{1}{5}$ , P(Y) = $\frac{1}{4}$ , P(Z) = $\frac{1}{3}$

Required probability:

= [ P(A)P(B){1−P(C)} ] + [ {1−P(A)}P(B)P(C) ] + [ P(A)P(C){1−P(B)} ] + P(A)P(B)P(C)

= $(\frac{1}{4} * \frac{1}{3} * \frac{4}{5}) + (\frac{3}{4} * \frac{1}{3} * \frac{1}{5}) + (\frac{2}{3} * \frac{1}{4} * \frac{1}{5}) + (\frac{1}{4} * \frac{1}{3} * \frac{1}{5})$

= $\frac{4}{60} + \frac{3}{60} + \frac{2}{60} + \frac{1}{60}$ = $\frac{10}{60}$ = $\frac{1}{6}$

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Filed Under: Probability

19 18865

Q:

In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ?

A) 693	B) 741
C) 528	D) 654

Answer & Explanation Answer: C) 528

Explanation:

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)
= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available
=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

29 18829

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