6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Ajay bought 15 kg of dal at the rate of Rs 14.50 per kg and 10 kg at the rate of Rs 13 per kg. He mixed the two and sold the mixture at the rate of Rs 15 per kg. What was his total gain in this transaction ?

A) Rs 1.10	B) Rs 11
C) Rs 16.50	D) Rs 27.50

Answer & Explanation Answer: D) Rs 27.50

Explanation:

Cost price of 25 kg = Rs. (15 x 14.50 + 10 x 13) = Rs. 347.50.
Sell price of 25 kg = Rs. (25 x 15) = Rs. 375.
profit = Rs. (375 — 347.50) = Rs. 27.50.

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Filed Under: Profit and Loss

47 22913

Q:

The ratio of investments of two partners is 11:12 and the ratio of their profits is 2 : 3. If A invested the money for 8 months , find for how much time B invested his money.

Answer

Suppose A invested Rs.11 for 8 months and B invested Rs. 12 for x months.

$\inline \therefore$ Ratio of investments of A and B

= (11 x 8) : (12 x x)

= 88 : 12x

$\inline \therefore$ $\inline \frac{88}{12x}=\frac{2}{3}\Rightarrow x=11$

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Subject: Partnership

26 22905

Q:

Three taps A,B and C can fill a tank in 12,15 and 20 hours respectively. If A is open all the time and B ,C are open for one hour each alternatively, the tank will be full in:

A) 6 hrs	B) 20/3 hrs
C) 7 hrs	D) 15/2 hrs

Answer & Explanation Answer: C) 7 hrs

Explanation:

$(A + B)' s 1 h o u r w o r k = (\frac{1}{12} + \frac{1}{15}) = \frac{9}{60} = \frac{3}{20}$

$(A + C)' s 1 h o u r w o r k = (\frac{1}{12} + \frac{1}{20}) = \frac{8}{60} = \frac{2}{15}$

$p a r t f i l l e d i n 2 h r s = (\frac{3}{20} + \frac{2}{15}) = \frac{17}{60}$

$p a r t f i l l e d i n 6 h r s = (3 * \frac{17}{60}) = \frac{17}{20}$

$r e m a i n i n g p a r t = (1 - \frac{17}{20}) = \frac{3}{20}$

Now, it is the turn of A and B (3/20) part is filled by A and B in 1 hour.

Therefore, Total time taken to fill the tank =(6+1)hrs= 7 hrs

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Filed Under: Pipes and Cistern

72 22905

Q:

Out of 17 applicants 8 boys and 9 girls. Two persons are to be selected for the job. Find the probability that at least one of the selected persons will be a girl.

A) 19/34	B) 5/4
C) 20/34	D) 25/34

Answer & Explanation Answer: D) 25/34

Explanation:

The events of selection of two person is redefined as first is a girl and second is a boy or first is boy and second is a girl or first is a girl and second is a girl.

So the required probability:
= $(\frac{8}{17} * \frac{9}{16}) + (\frac{9}{17} * \frac{8}{16}) + (\frac{8}{17} * \frac{7}{16})$

= $\frac{9}{34} + \frac{9}{34} + \frac{7}{34}$
= $\frac{25}{34}$

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Filed Under: Probability

21 22902

Q:

In an examination, 34% of the students failed in Mathematics and 42% faiied in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

A) 34 %	B) 44 %
C) 54 %	D) 64 %

Answer & Explanation Answer: B) 44 %

Explanation:

n (A) = 34, n (B) = 42, n (A ∩ B) = 20.

So, n (A U B) = n (A) + n(B) - n(A ∩B) = 34 + 42 - 20 = 56.

Percentage failed in either or both the subjects = 56.

Hence, percentage passed = (100 - 66)% = 44%.

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Filed Under: Percentage

28 22852

Q:

In a pot, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk, the pot would be full and ratio of milk and water would become 6 : 5. Find the capacity of the pot ?

A) 11 lit	B) 22 lit
C) 33 lit	D) 44 lit

Answer & Explanation Answer: B) 22 lit

Explanation:

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

43 22823

Q:

If each side of a square is increased by 25%, find the percentage change in its area.

A) 56.25%	B) 36.25%
C) 16.25%	D) 12.25%

Answer & Explanation Answer: A) 56.25%

Explanation:

Let each side of the square be a. Then, area = . $a^{2}$
New side = $\frac{125 a}{100} = \frac{5 a}{4}$ . New area = ${(\frac{5 a}{4})}^{2}$ = $(\frac{25 a^{2}}{16})$

Increase in area = $\frac{25 a^{2}}{16} - a^{2} = \frac{9 a^{2}}{16}$
Increase% = $[\frac{9 a^{2}}{16} * \frac{1}{a^{2}} * 100]$ % = 56.25%.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

39 22735

Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq. cm, find its height

A) 6	B) 7
C) 8	D) 9

Answer & Explanation Answer: A) 6

Explanation:

Let the height of the parallelogram be x. cm. Then, base = (2x) cm.

$2 x \times x = 72 = > 2 x^{2} = 72 = > x = 6$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

32 22730

Quantitative Aptitude - Arithmetic Ability Questions

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